平均会话持续时间度量,这是以前在Firebase分析仪表板中可用的。但是现在,它没有在Firebase分析仪表板上使用。现在,我们只看到“每个用户的参与”。是每个用户和Avg的订婚。会话时间和时间是一样的吗?如何提取阿夫格。来自Fiebase分析的会话持续时间?如何在Bigquery中查询提取Avg。来自Firebase的会话持续时间度量。在这里输入图像描述
发布于 2019-04-25 11:30:01
每个用户的约定与Avg不一样。会议期间。每个用户的参与度是指用户每天在应用程序中花费的时间,而不是会话。
with timeline as
(
select
user_pseudo_id
, event_timestamp
, lag(event_timestamp, 1) over (partition by user_pseudo_id order by event_timestamp) as prev_event_timestamp
from
`YYYYY.analytics_XXXXX.events_*`
where
-- at first - a sliding period - how many days in the past we are looking into:
_table_suffix
between format_date("%Y%m%d", date_sub(current_date, interval 10 day))
and format_date("%Y%m%d", date_sub(current_date, interval 1 day))
)
, session_timeline as
(
select
user_pseudo_id
, event_timestamp
, case
when
-- half a hour period - a threshold for a new 'session'
event_timestamp - prev_event_timestamp >= (30*60*1000*1000)
or
prev_event_timestamp is null
then 1
else 0
end as is_new_session_flag
from
timeline
)
, marked_sessions as
(
select
user_pseudo_id
, event_timestamp
, sum(is_new_session_flag) over (partition by user_pseudo_id order by event_timestamp) AS user_session_id
from session_timeline
)
, measured_sessions as
(
select
user_pseudo_id
, user_session_id
-- session duration in seconds with 2 digits after the point
, round((max(event_timestamp) - min(event_timestamp))/ (1000 * 1000), 2) as session_duration
from
marked_sessions
group by
user_pseudo_id
, user_session_id
having
-- let's count only sessions longer than 10 seconds
session_duration >= 10
)
select
count(1) as number_of_sessions
, round(avg(session_duration), 2) as average_session_duration_in_sec
from
measured_sessions
有关如何获取event_date和app_info.id的附加问题,请参见以下查询:
with timeline as
(
select
event_date,app_info.id,user_pseudo_id
, event_timestamp
, lag(event_timestamp, 1) over (partition by user_pseudo_id order by event_timestamp) as prev_event_timestamp
from
`<table>_*`
where
-- at first - a sliding period - how many days in the past we are looking into:
_table_suffix
between format_date("%Y%m%d", date_sub(current_date, interval 10 day))
and format_date("%Y%m%d", date_sub(current_date, interval 1 day))
)
, session_timeline as
(
select
event_date,id,
user_pseudo_id
, event_timestamp
, case
when
-- half a hour period - a threshold for a new 'session'
event_timestamp - prev_event_timestamp >= (30*60*1000*1000)
or
prev_event_timestamp is null
then 1
else 0
end as is_new_session_flag
from
timeline
)
, marked_sessions as
(
select
event_date,id, user_pseudo_id
, event_timestamp
, sum(is_new_session_flag) over (partition by user_pseudo_id order by event_timestamp) AS user_session_id
from session_timeline
)
, measured_sessions as
(
select
event_date,id, user_pseudo_id
, user_session_id
-- session duration in seconds with 2 digits after the point
, round((max(event_timestamp) - min(event_timestamp))/ (1000 * 1000), 2) as session_duration
from
marked_sessions
group by
event_date, id, user_pseudo_id
, user_session_id
having
-- let's count only sessions longer than 10 seconds
session_duration >= 10
)
select
event_date, id, count(1) as number_of_sessions
, round(avg(session_duration), 2) as average_session_duration_in_sec
from
measured_sessions
group by event_date, id
发布于 2020-04-15 13:48:34
每个会话(自2019年12月以来定义的:https://firebase.googleblog.com/2018/12/new-changes-sessions-user-engagement.html)都有一个session_id (除了其他参数)。我认为计算平均会话持续时间的最安全和最健壮的方法是将数据提取到BigQuery,然后按会话计算第一个时间戳和最后一个时间戳之间的平均差值。为此,需要对event_params数组进行扁平化处理。例如,AWS雅典娜就是这样做的:
WITH arrays_flattened AS
(SELECT params.key AS key,
params.value.int_value AS id,
event_timestamp,
event_date
FROM your_database
CROSS JOIN UNNEST(event_params) AS t(params)
WHERE params.key = 'ga_session_id'), duration AS
(SELECT MAX(event_timestamp)-MIN(event_timestamp) AS duration
FROM arrays_flattened
WHERE key = 'ga_session_id'
GROUP BY id)
SELECT AVG(duration)
FROM durationhttps://stackoverflow.com/questions/55847381
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