我正在处理来自Server和MySQL的两个相同的表,我的最终目标是能够通过PHP同步它们的内容。我为此做了一个previous post,我发现我的代码不起作用的原因是单引号扰乱了我的SQL语法。然后,我将表转换为使用PDO,因为我听到准备语句/绑定param是更有效的。但是,我的代码仍然没有正确地转义单引号。我已经查过过去的帖子了,但没有一个能解决我的问题。以下是代码:
<?php
$serverName = "<servername>";
$connectionInfo_mssql = array("Database"=>"<dbname>", "CharacterSet"=>"UTF-8");
try
{
$conn_mssql = new PDO("sqlsrv:Server=$serverName;Database=<dbname>");
$conn_mssql->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$conn_mysql = new PDO("mysql:host=localhost;dbname=<dbname>", "", "");
$conn_mysql->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//SELECT FROM SQL SERVER DB
$mssql_array = array();
$mssql_query = $conn_mssql->prepare("SELECT * FROM Customers");
$mssql_query->execute();
while($row = $mssql_query->fetch(PDO::FETCH_BOTH))
{
$mssql_array[] = array('ID' => $row['ID'],
'Name' => $row["Name"],
'Address' => $row['Address'],
'Email' => $row['Email']);
}
foreach($mssql_array as $key => $value)
{
//SELECT FROM MySQL DB
$mysql_query = $conn_mysql->prepare("SELECT COUNT(*) FROM Customers WHERE ID ='".$value['ID']."'
AND Name = '".$value["Name"]."'
AND Address = '".$value['Address']."'
AND Email = '".$value['Email']."' ");
$mysql_query->execute();
$num_rows = $mysql_query->fetchColumn();
if ($num_rows == 0)
{
//INSERT INTO MySQL DB
$sql = $conn_mysql->prepare("INSERT INTO Customers VALUES (:ID, :Name, :Address, :Email)");
$params = array(':ID' => $value["ID"], ':Name' => $value["Name"], ':Address' => $value["Address"], ':Email' => $value["Email"]);
$sql->execute($params); //this is where the error occurs
}
}
echo 'Table Customers from MS SQL DB and table Customers from MySQL DB are now synced!'."<br>";
echo "<a href='table_updater.php'>Go back to updater</a>";
}
catch(PDOException $e)
{
echo "Error: " . $e->getMessage();
}
?>基本上,它选择了Server表的所有内容并将其放入MySQL中,但是由于我的一行的值为"Jojo's“,所以它只会因为单引号而给出一个错误。我所犯的错误是
错误: SQLSTATE42000:语法错误或访问冲突: 1064您的SQL语法出现了错误;检查与MariaDB服务器版本对应的手册,以获得使用“s”和Address =‘IDK’的正确语法。
这很大程度上告诉我我不会逃避单引号。
任何想法都是非常感谢的!
发布于 2019-04-23 11:27:28
问题不在于INSERT语句,而在于SELECT语句。从错误中可以看到,它无法解释select查询的一部分。所以正确的代码如下所示:
//SELECT FROM MySQL DB
$mysql_query = $conn_mysql->prepare("SELECT COUNT(*) FROM Customers WHERE ID = :ID
AND Name = :Name
AND Address = :Address
AND Email = :Email ");
$params = [':ID' => $value['ID'], ':Name' => $value['Name'], ':Address' => $value['Address'], ':Email' => $value['Email']];
$mysql_query->execute($params);为了进一步解释,如果没有占位符,如果名称中有引号,则select查询可能如下所示:
SELECT COUNT(*) FROM Customers WHERE ID = '123'
AND Name = 'As'd, dfg' # <- Problem here
AND Address = 'some address'
AND Email = 'email@example.com'对于记录,应始终对代码中不受控制的任何值使用占位符。即使这是用于SELECT语句或您信任的数据源。这防止意外注入和处理任何类型的字符。
https://stackoverflow.com/questions/55809899
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