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Python:从FuzzyWuzzy ExtractOne()返回Pandas FuzzyWuzzy
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Stack Overflow用户
提问于 2019-04-08 08:09:21
回答 1查看 1.2K关注 0票数 1

我有两个Pandas DataFrames (人名),一个小行(200+行),另一个很大(100k+行)。它们都有相似的头,但是大的头也有一个唯一的ID,如下所示:

代码语言:javascript
复制
Small: LST_NM, FRST_NM, CITY
Big: LST_NM, FRST_NM, CITY, UNIQUE_ID

小:df2 = pd.DataFrame([['Doe','John','New York'], ['Obama', 'Barack', 'New York']], columns = ['FRST_NM', 'LST_NM', 'CITY_NM'])

大:df = pd.DataFrame([['Doe','John','New York', 'N1'], ['Obama', 'Barack Hussein', 'New York', 'N2'], ['Obama', 'Michelle', 'Chicago', 'N3'], ['Trump', 'Donald', 'New York', 'N4']], columns = ['FRST_NM', 'LST_NM', 'CITY_NM', 'UNIQUE_ID'])

我使用以下代码:

代码语言:javascript
复制
import itertools
from fuzzywuzzy import fuzz
from fuzzywuzzy import process
import time
import pandas as pd
import multiprocessing as mp
from unidecode import unidecode
import re

#read the CSV files;
df = pd.read_csv("BIG.csv", encoding="utf-8")
df2 = pd.read_csv("SMALL.csv", encoding="utf-8")

#create function to clean the columns
def clean_column(column):
    column = unidecode(column)
    column = re.sub('\n', ' ', column)
    column = re.sub('-', ' ', column)
    column = re.sub('/', ' ', column)
    column = re.sub("'", '', column)
    column = re.sub(",", '', column)
    column = re.sub(":", ' ', column)
    column = re.sub('  +', ' ', column)
    column = column.strip().strip('"').strip("'").lower().strip()
    if not column :
        column = None
    return column

#Normalize, create FULL_NM by combining FRST_NM / LST_NM and then create MIN_CITY as the first three chars from CITY_NM:
df['FULL_NM'] = (df['LST_NM'] + ' ' + df['FRST_NM']).apply(lambda x: fuzz._process_and_sort(clean_column(x), True, True))
df['MIN_CITY'] = (df['CITY_NM']).astype(str).apply(lambda x: clean_column(x[:3]))

df2['FULL_NM'] = (df2['LST_NM'] + ' ' + df2['FRST_NM']).apply(lambda x: fuzz._process_and_sort(clean_column(x), True, True))
df2['MIN_CITY'] = (df2['CITY_NM']).astype(str).apply(lambda x: clean_column(x[:3]))

#create match1 function; it uses the FULL_NM as lookup field
def match1(x, choices, scorer, cutoff):
        match = process.extractOne(x['FULL_NM'], choices=choices.loc[choices['MIN_CITY'] == x['MIN_CITY'],'FULL_NM'], 
                                   scorer=scorer, 
                                   score_cutoff=cutoff)
        if match:
            return match[0]

#and finally... create the MATCH_NM column by applying match1 function as following:
df2['MATCH_NAME'] = df2.apply(match1, args=(df, fuzz.token_set_ratio, 80), axis=1)

我想查找从大到小的信息,带来UNIQUE_ID。为了加速这个过程,我创建了更小的块(使用前三个城市字母)。这个新列(在两个DataFrames中创建)被命名为MIN_CITY。

上面的代码运行良好,但它只带来匹配的名称(MATCH_NAME)。我不想逆转(从小到大,然后过滤)。如何从UNIQUE_ID ()获得process.ExtractOne?我需要指出的是,我对Python / Pandas / FuzzyWuzzy非常陌生。

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回答 1

Stack Overflow用户

回答已采纳

发布于 2019-04-08 10:02:06

请查一下模糊匹配器

代码语言:javascript
复制
from fuzzymatcher import link_table, fuzzy_left_join

left_on = ['FULL_NM']
right_on = ['FULL_NM']

fuzzy_left_join(df2, df, left_on, right_on)

给出一张表:

代码语言:javascript
复制
best_match_score    __id_left   __id_right  FRST_NM_left    LST_NM_left CITY_NM_left    FULL_NM_left    MIN_CITY_left   MATCH_NAME  FRST_NM_right   LST_NM_right    CITY_NM_right   UNIQUE_ID   FULL_NM_right   MIN_CITY_right
0   0.167755    0_left  0_right Doe John    New York    doe john    new doe john    Doe John    New York    N1  doe john    new
1   0.081166    1_left  1_right Obama   Barack  New York    barack obama    new barack hussein obama    Obama   Barack Hussein  New York    N2  barack hussein obama    new

这里有一些示例

如果必须坚持使用fuzzy_wuzzy.process.extractOne,则可以匹配并从匹配的名称中找到unique_id,如下所示:

代码语言:javascript
复制
def match1(x, choices, scorer, cutoff):
        match = process.extractOne(x['FULL_NM'], choices=choices.loc[choices['MIN_CITY'] == x['MIN_CITY'],'FULL_NM'], 
                                   scorer=scorer, 
                                   score_cutoff=cutoff)
        if match:
            return choices[choices['FULL_NM'] == 'doe john'].UNIQUE_ID[0]
票数 2
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/55568849

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