把列表变成字典

Question

我知道这个问题已经问过无数次了，但我很难想出解决问题的办法。

这是我的密码：

try:
    dict1={}
    main_list = [line.rstrip() for line in open("food01.csv")]
    print(main_list)
except IOError:
    print("Error opening file")

文件(CSV)的输出：

['lion,gazelle', 'jackal,grass,zebra,gazelle', 'gazelle,grass,acacia leaves', 'zebra,grass']

我想要的是这样的列表字典：

{'lion':['gazelle'],'jackal':['grass,zebra,gazelle'],'gazelle':['grass,acacia leaves'],'zebra':['grass']}

Answer 1

您可以使用这样的嵌套dict理解：

{first: rest for cols in rows for first, *rest in (cols.split(','),)}

因此，鉴于：

rows = ['lion,gazelle', 'jackal,grass,zebra,gazelle', 'gazelle,grass,acacia leaves', 'zebra,grass']

这将返回：

{'lion': ['gazelle'], 'jackal': ['grass', 'zebra', 'gazelle'], 'gazelle': ['grass', 'acacia leaves'], 'zebra': ['grass']}

Answer 2

这样就行了。

lst = ['lion,gazelle', 'jackal,grass,zebra,gazelle', 'gazelle,grass,acacia leaves', 'zebra,grass']

dct = {}
for l in lst:
    items = l.split(',')
    dct[items[0]] = items[1:]

print(dct)
#{'lion': ['gazelle'], 'jackal': ['grass', 'zebra', 'gazelle'], 'gazelle': ['grass', 'acacia leaves'], 'zebra': ['grass']}

Answer 3

你需要有两个列表来做这个。1对于键1的值，尝试将捕食者和捕食者分成2个列表，然后使用zip将它们合并到字典中。

keys = ["lion", "jackal", 'gazelle']
values = [["gazelle"], ["grass, zebra, gazelle"], ["grass, acacia leaves"]]
dict1 = dict(zip(keys, values))
print(dict1)