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社区首页 >问答首页 >从wrk输出中提取文本

从wrk输出中提取文本
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Stack Overflow用户
提问于 2019-04-04 14:22:24
回答 1查看 371关注 0票数 1

我正在使用wrk2作为Jenkins的一项工作运行一个负载测试。我想将负载测试的结果发送到Graylog,但是我只想存储请求/Sec和平均延迟。

以下是输出的样子:

代码语言:javascript
复制
Running 30s test @ https://example.com

1 threads and 100 connections
  Thread calibration: mean lat.: 8338.285ms, rate sampling interval: 19202ms
  Thread Stats   Avg      Stdev     Max   +/- Stdev
    Latency    16.20s     6.17s   29.64s    65.74%
    Req/Sec     5.00      0.00     5.00    100.00%
  Latency Distribution (HdrHistogram - Recorded Latency)
 50.000%   15.72s 
 75.000%   20.81s 
 90.000%   24.58s 
 99.000%   29.13s 
 99.900%   29.66s 
 99.990%   29.66s 
 99.999%   29.66s 
100.000%   29.66s 

  Detailed Percentile spectrum:
       Value   Percentile   TotalCount 1/(1-Percentile)

    4497.407     0.000000            1         1.00
    7561.215     0.100000           11         1.11
   11100.159     0.200000           22         1.25
   12582.911     0.300000           33         1.43
   14565.375     0.400000           44         1.67
   15720.447     0.500000           54         2.00
   16416.767     0.550000           60         2.22
   17301.503     0.600000           65         2.50
   18464.767     0.650000           71         2.86
   19185.663     0.700000           76         3.33
   20807.679     0.750000           81         4.00
   21479.423     0.775000           84         4.44
   22347.775     0.800000           87         5.00
   22527.999     0.825000           90         5.71
   23216.127     0.850000           93         6.67
   23478.271     0.875000           95         8.00
   23805.951     0.887500           96         8.89
   24723.455     0.900000           98        10.00
   25067.519     0.912500           99        11.43
   25395.199     0.925000          101        13.33
   26525.695     0.937500          102        16.00
   26525.695     0.943750          102        17.78
   26705.919     0.950000          103        20.00
   28065.791     0.956250          104        22.86
   28065.791     0.962500          104        26.67
   28377.087     0.968750          105        32.00
   28377.087     0.971875          105        35.56
   28475.391     0.975000          106        40.00
   28475.391     0.978125          106        45.71
   28475.391     0.981250          106        53.33
   29130.751     0.984375          107        64.00
   29130.751     0.985938          107        71.11
   29130.751     0.987500          107        80.00
   29130.751     0.989062          107        91.43
   29130.751     0.990625          107       106.67
   29655.039     0.992188          108       128.00
   29655.039     1.000000          108          inf
#[Mean    =    16199.756, StdDeviation   =     6170.105]
#[Max     =    29638.656, Total count    =          108]
#[Buckets =           27, SubBuckets     =         2048]
----------------------------------------------------------
  130 requests in 30.02s, 13.44MB read
  Socket errors: connect 0, read 0, write 0, timeout 1192
Requests/sec:      4.33
Transfer/sec:    458.47KB

有人知道我如何提取请求/秒(底部)和作为JSON参数发送的平均延迟吗?

预期的输出是:"latency": 16.2, "requests_per_second": 4.33

EN

回答 1

Stack Overflow用户

回答已采纳

发布于 2019-04-04 14:48:44

您没有提供预期的输出,所以您的问题不清楚,但这是您想要的吗?

代码语言:javascript
复制
$ awk 'BEGIN{a["Latency"]; a["Requests/sec:"]} ($1 in a) && ($2 ~ /[0-9]/){print $1, $2}' file
Latency 16.20s
Requests/sec: 4.33

根据您在问题中添加的预期输出进行更新:

代码语言:javascript
复制
$ awk '
    BEGIN { map["Latency"]="latency"; map["Requests/sec:"]="requests_per_second" }
    ($1 in map) && ($2 ~ /[0-9]/) { printf "%s\"%s\": %s", ofs, map[$1], $2+0; ofs=", " }
    END { print "" }
' file
"latency": 16.2, "requests_per_second": 4.33
票数 2
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/55518357

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