我有一个数组,成功地转换成带有EcmaScript-6函数的字符串格式。但是,我如何使用EcmaScript-3来完成这个任务呢?接收端点需要一个ES3函数。
原始数组:
formdata: [
1: {name: "gender", value: "F", focus: 0, type: "radio"}
2: {name: "firstname", value: "empty", focus: 0, type: "text"}
3: {name: "lastname", value: "empty", focus: 0, type: "text"}
4: {name: "birthday", value: "empty", focus: 0, type: "text"}
5: {name: "street", value: "empty", focus: 0, type: "text"}
6: {name: "streetNo", value: "empty", focus: 0, type: "text"}
]必需的字符串格式
let formdata = gender.radio|F|0;firstName.text|empty|1;lastName.text|empty|0;street.text|empty|0;houseNumber.text|empty|0;zip.text|empty|0;city.text|empty|0;country.select-one|de|0;birthdate-day.text|empty|0;birthdate-month.text|empty|0;birthdate-year.text|empty|0;email.email|empty|0;code.text|filled_out|0我的工作解决方案与ES6:
let res = formdata.map(({name,value,focus,type}) => `${name}.${type}|${value}|${focus}`).join(';')关于转换为ES3:的看法
var res = formdata.map(({name,value,focus,type}) {
("name" + "." + "type" + "|" + "value" + "focus").join(;)
}这个解决方案显然不起作用,而且我也不确定它是否有效的ES3 JavaScript。
谢谢!
发布于 2019-04-04 05:32:04
ES3尝试中的问题:
.join(;)是无效的JavaScript。.join(";")是。.map是在ES5中引入的所以:
var formdata = [{name: "gender", value: "F", focus: 0, type: "radio"},{name: "firstname", value: "empty", focus: 0, type: "text"},{name: "lastname", value: "empty", focus: 0, type: "text"}, {name: "birthday", value: "empty", focus: 0, type: "text"},{name: "street", value: "empty", focus: 0, type: "text"},{name: "streetNo", value: "empty", focus: 0, type: "text"},];
var arr = [];
for (var i = 0; i < formdata.length; i++) {
var elem = formdata[i];
arr.push(elem.name + "." + elem.type + "|" + elem.value + "|" + elem.focus);
}
var str = arr.join(";");
console.log(str);
https://stackoverflow.com/questions/55508261
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