如何从javascript中的另一个数组中删除数组

Question

0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
1: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
2: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}

我想删除数组中的0:{}数组。我怎么才能移除？以及如何找到第一项的价值？

Answer 1

我从您的问题中了解到，您必须从Array2中删除Array1，如下所示，

Array1 = 0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
         1: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}
         2: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}

Array2 = 0: {id: 1553825061863, name: "Thai Milk Tea", qty: "1", total_amount: 9500, toppings: 500, …}

如果是这样，只需使用过滤器函数，如下所示。

    var data = Array1; 
    var selectedRows = Array2; 

    var unSelectedRows = [];
    var unSelectedRows = data.filter( function( el ) {
      return !selectedRows.includes( el );
    } );

你可以在unSelectedRows阵列中得到第1和第2元素.

Answer 2

由于数组的第一个元素总是索引0，所以可以使用Array.prototype.shift删除第一个元素：

​

const array = [{
  id: 1553825061863,
  name: "Thai Milk Tea",
  qty: "1",
  total_amount: 9500,
  toppings: 500
}, {
  id: 1553825061863,
  name: "Thai Milk Tea",
  qty: "1",
  total_amount: 9500,
  toppings: 500
}, {
  id: 1553825061863,
  name: "Thai Milk Tea",
  qty: "1",
  total_amount: 9500,
  toppings: 500
}];

let remainingArray = array;
remainingArray.shift();

console.log(remainingArray);

.as-console-wrapper {
  max-height: 100% !important;
  top: auto;
}

​

Answer 3

//try this on your console. You can use the shift operator to shift the first element.
//also to remove the last element use pop
>>var myArr = [{id : 1, name: "A"}, {id: 2, name: "B"}, {id:3, name: "C"}];
undefined
>>myArr.shift(0);
{id: 1, name: "A"}
>>myArr
0: {id: 2, name: "B"}
1: {id: 3, name: "C"}

下面是关于Array.protoType.shift()的详细链接，它删除了第一个元素：

• Objects/Array/shift