首先,感谢您提供了一个充满活力的、有帮助的社区。这很有帮助!我在OSX 10.13。我在mac上安装了Python3和2,并使用命令(python3 -m pip flake8)下载flake8。一切似乎进展顺利,但当我打字时:
$ flake8 --版本
上面写着“命令找不到”。我想在崇高的文本3中使用flake8,但是现在,它似乎没有指向正确的位置。如果我输入:
$ pip3 -f flake8
它找到位置(下面的代码)。任何帮助都将不胜感激。
Name: flake8
Version: 3.7.7
Summary: the modular source code checker: pep8, pyflakes and co
Home-page: https://gitlab.com/pycqa/flake8
Author: Tarek Ziade
Author-email: tarek@ziade.org
License: MIT
Location: /Library/Frameworks/Python.framework/Versions/3.7/lib/python3.7/site-packages
Requires: entrypoints, pycodestyle, pyflakes, mccabe
Required-by:
Files:
../../../bin/flake8
flake8-3.7.7.dist-info/INSTALLER
flake8-3.7.7.dist-info/LICENSE
flake8-3.7.7.dist-info/METADATA
flake8-3.7.7.dist-info/RECORD
flake8-3.7.7.dist-info/WHEEL
flake8-3.7.7.dist-info/entry_points.txt
flake8-3.7.7.dist-info/top_level.txt
flake8/__init__.py
flake8/__main__.py
flake8/__pycache__/__init__.cpython-37.pyc
flake8/__pycache__/__main__.cpython-37.pyc
flake8/__pycache__/checker.cpython-37.pyc
flake8/__pycache__/defaults.cpython-37.pyc
flake8/__pycache__/exceptions.cpython-37.pyc
flake8/__pycache__/processor.cpython-37.pyc
flake8/__pycache__/statistics.cpython-37.pyc
flake8/__pycache__/style_guide.cpython-37.pyc
flake8/__pycache__/utils.cpython-37.pyc
flake8/api/__init__.py
flake8/api/__pycache__/__init__.cpython-37.pyc
flake8/api/__pycache__/legacy.cpython-37.pyc
flake8/api/legacy.py
flake8/checker.py
flake8/defaults.py
flake8/exceptions.py
flake8/formatting/__init__.py
flake8/formatting/__pycache__/__init__.cpython-37.pyc
flake8/formatting/__pycache__/base.cpython-37.pyc
flake8/formatting/__pycache__/default.cpython-37.pyc
flake8/formatting/base.py
flake8/formatting/default.py
flake8/main/__init__.py
flake8/main/__pycache__/__init__.cpython-37.pyc
flake8/main/__pycache__/application.cpython-37.pyc
flake8/main/__pycache__/cli.cpython-37.pyc
flake8/main/__pycache__/debug.cpython-37.pyc
flake8/main/__pycache__/git.cpython-37.pyc
flake8/main/__pycache__/mercurial.cpython-37.pyc
flake8/main/__pycache__/options.cpython-37.pyc
flake8/main/__pycache__/setuptools_command.cpython-37.pyc
flake8/main/__pycache__/vcs.cpython-37.pyc
flake8/main/application.py
flake8/main/cli.py
flake8/main/debug.py
flake8/main/git.py
flake8/main/mercurial.py
flake8/main/options.py
flake8/main/setuptools_command.py
flake8/main/vcs.py
flake8/options/__init__.py
flake8/options/__pycache__/__init__.cpython-37.pyc
flake8/options/__pycache__/aggregator.cpython-37.pyc
flake8/options/__pycache__/config.cpython-37.pyc
flake8/options/__pycache__/manager.cpython-37.pyc
flake8/options/aggregator.py
flake8/options/config.py
flake8/options/manager.py
flake8/plugins/__init__.py
flake8/plugins/__pycache__/__init__.cpython-37.pyc
flake8/plugins/__pycache__/manager.cpython-37.pyc
flake8/plugins/__pycache__/pyflakes.cpython-37.pyc
flake8/plugins/manager.py
flake8/plugins/pyflakes.py
flake8/processor.py
flake8/statistics.py
flake8/style_guide.py
flake8/utils.py我相信代码的输出要求我提供更多的依赖关系,但不确定是什么。谢谢。
发布于 2019-03-23 20:58:55
这意味着flake8可能不在$PATH环境变量中。尝试which flake8来确定。如果它不存在,请确保添加它。
例如在我的工作环境中
$ which flake8
/Library/Frameworks/Python.framework/Versions/3.6/bin/flake8在我的.bash_profile中,我使用它声明PATH环境变量
PATH="/Library/Frameworks/Python.framework/Versions/3.6/bin:/usr/local/bin:...."
export $PATHhttps://stackoverflow.com/questions/55317947
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