嗨,我正在尝试打印多个数组与选定的块e.x。2/3但我没有得到确切的结果。我需要些帮助。
这是我的节目
<?php
$process_block = 2;// this is the block
$args = array(
0=> 16083,
1=> 16090);
$user_id_start = $args[0];
$user_id_end = $args[1];
$end_page = ($user_id_end - $user_id_start)/$process_block ;
if ($end_page > floor($end_page)){
$end_page = floor($end_page)+1;
}
for($i=1; $i<=$end_page; $i++){
if($i==$end_page){
$id_from = ($user_id_start + ($i-1) * $process_block + 1);
$id_to = $user_id_end;
}elseif($i==1){
$id_from = $user_id_start;
$id_to = $user_id_start + $i * $process_block;
}else{
$id_from = ($user_id_start + ($i-1) * $process_block + 1);
$id_to = $user_id_start + $i * $process_block;
}
$param['id_from'] = isset($id_from) ? $id_from : '';
$param['id_to'] = isset($id_to) ? $id_to : '';
print_r($param);
}
?>它正在产生的产出:
Array
(
[id_from] => 16083
[id_to] => 16085
)
Array
(
[id_from] => 16086
[id_to] => 16087
)
Array
(
[id_from] => 16088
[id_to] => 16089
)
Array
(
[id_from] => 16090
[id_to] => 16090
)我期望的数组应该是这样的。两个数字之间的差
Array
(
[id_from] => 16083
[id_to] => 16085
)
Array
(
[id_from] => 16086
[id_to] => 16088
)
Array
(
[id_from] => 16089
[id_to] => 16090
)发布于 2019-03-21 06:05:22
我想我可以在一段时间内把这件事编出来。但这可能是版本..。4?我觉得应该有一个更简单的解决方案,但我肯定找不到。它也应该处理范围大小的变化。
<?php
$process_block = 3;// this is the block
$args = array(
0=> 16083,
1=> 16090);
$user_id_start = $args[0];
$user_id_end = $args[1];
$diff = $user_id_end - $user_id_start;
$pages = ceil(($user_id_end - $user_id_start) / $process_block);
for($i=0; $i<=$pages; $i++){
if (($user_id_start+$i*$process_block)>$user_id_end)break;
echo $i.'--'.($user_id_start+$i*$process_block).':::';
$param['id_from'] = $i*$process_block+$user_id_start;
$page_end = ($i+1) * $process_block+$user_id_start-1;
$param['id_to'] = $page_end>$user_id_end ? $user_id_end : $page_end;
print_r($param);
}
?>https://stackoverflow.com/questions/55273964
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