我见过很多人在C-MAC代(零售MAC)上寻求帮助.这个问题也包含了答案。这会让你有足够的时间。我已经用真卡测试了这个功能,它运行得很好。
发布于 2019-03-15 09:30:56
注:
公共静态byte[] generateCmac(字节[]apdu,byte[]sMacSessionKey,byte[]icv)抛出异常{
if(sMacSessionKey.length == 16) {
byte []temp = sMacSessionKey.clone();
sMacSessionKey = new byte[24];
System.arraycopy(temp,0,sMacSessionKey,0,temp.length);
System.arraycopy(temp,0,sMacSessionKey,16,8);
}
byte []cMac = new byte[8];
byte []padding = {(byte)0x80,0x00,0x00,0x00,0x00,0x00,0x00,0x00,};
int paddingRequired = 8 - (apdu.length) %8;
byte[] data = new byte[apdu.length + paddingRequired];
System.arraycopy(apdu, 0, data, 0, apdu.length);
System.arraycopy(padding, 0, data, apdu.length,paddingRequired);
Cipher cipher = Cipher.getInstance("DESede/CBC/NoPadding");
Cipher singleDesCipher = Cipher.getInstance("DES/CBC/NoPadding",
"SunJCE");
SecretKeySpec desSingleKey = new SecretKeySpec(sMacSessionKey, 0, 8,
"DES");
SecretKey secretKey = new SecretKeySpec(sMacSessionKey, "DESede");
// Calculate the first n - 1 block. For this case, n = 1
IvParameterSpec ivSpec = new IvParameterSpec(icv);
singleDesCipher.init(Cipher.ENCRYPT_MODE, desSingleKey, ivSpec);
// byte ivForLastBlock[] = singleDesCipher.doFinal(data, 0, 8);
int blocks = data.length / 8;
for (int i = 0; i < blocks - 1; i++) {
singleDesCipher.init(Cipher.ENCRYPT_MODE, desSingleKey, ivSpec);
byte[] block = singleDesCipher.doFinal(data, i * 8, 8);
ivSpec = new IvParameterSpec(block);
}
int offset = (blocks - 1) * 8;
cipher.init(Cipher.ENCRYPT_MODE, secretKey, ivSpec);
cMac = cipher.doFinal(data, offset, 8);
ivSpec = new IvParameterSpec(new byte[8]);
singleDesCipher.init(Cipher.ENCRYPT_MODE, desSingleKey, ivSpec);
icvNextCommand = singleDesCipher.doFinal(cMac);
System.out.println("icvNextCommand"+Utility.bytesToHex(icvNextCommand, icvNextCommand.length));
return cMac;
}发布于 2019-04-14 23:15:49
一种更简单的方法是使用Signature.ALG_DES_MAC8_ISO9797_1_M2_ALG3 (如果卡支持的话)来计算SCP02中C的零售MAC值。
注意:CMAC是一个消息身份验证代码,根本不在SCP02中使用。
PC端的EDIT>考虑来自弹跳城堡的ISO9797Alg3Mac。
https://stackoverflow.com/questions/55179415
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