Swift:条件字符串转换

Question

如何根据以下条件转换给定的字符串？

• 所有大于3个字符的单词应翻译成“宾果”。
• 必须保持资本化
• 单词中的标点符号(例如，我们会)可以被丢弃，所有其他标点符号都必须保持。

到目前为止我的代码：

// *** Using For loop ***
var text = "I'll BUY THAT for a $1234 dollars!"
var textComponents = text.components(separatedBy: .whitespacesAndNewlines)

for i in 0 ..< textComponents.count {
    // -TODO: add code to maintain capitalization & punctuation (i.e.: !, $)
    if textComponents[i].count > 3 {
        textComponents[i] = "bingo"
    }
}

textComponents.joined(separator: " ")


// *** Using Map/Filter ***
var text = "I'll BUY THAT for a $1234 dollars!"
var textComponents = text.components(separatedBy: .whitespacesAndNewlines)
textComponents.map {
    // -TODO: add code to maintain capitalization & punctuation (i.e.: !, $)
    if $0.count > 3 {
        // ERROR: Not able reassign $0
        $0 = "bingo"
    }
}

示例

给出了一个字符串：：“我要花1234美元买它！”

预期翻译：“宾果买宾果为$bingo宾果！”

Answer 1

您可能至少需要三个替换词，如下所示。它可能不是完整的，因为你的需求现在没有那么固定。

  let raw = "I'll BUY THAT for a $1234 dollar!".replacingOccurrences(of: "\\b[A-Z][[a-z0-9]\\']{3,}", with: "Bingo", options: .regularExpression, range: nil)
.replacingOccurrences(of: "\\b[A-Z\\']{4,}", with: "BINGO", options: .regularExpression, range: nil)
.replacingOccurrences(of: "\\b[a-z'\\d]{4,}", with: "bingo", options: .regularExpression, range: nil)

  print(raw) // Bingo BUY BINGO for a $bingo bingo!