计算javascript对象数组中重复项的平均值

Question

我有一组对象：

[
{"market": "Qacha's nek","commodity": 55,"price": "90","month": "04","year": "2017"}, 
{"market": "Mohales Hoek","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Mafeteng","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Maseru","commodity": 55,"price": "69","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "66","month": "04","year": "2017"}, 
{"market": "Leribe","commodity": 55,"price": "64","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "65","month": "04","year": "2017"}, 
{"market": "Thaba-Tseka","commodity": 55,"price": "82","month": "04","year": "2017"},
{"market": "Thaba-Tseka","commodity": 55,"price": "81","month": "04","year": "2017"},
{"market": "Maseru",    "commodity": 55,"price": "74,99","month": "04","year": "2017"}
]

我试着按平均价格来聚合复制。

因此，识别重复行的关键是除price之外的所有属性，这些属性必须按平均值进行聚合。

例如，在上面的数据中，第5和第7行：

5) "market": "Butha-Buthe","commodity": 55,"price": "66","month": "04","year": "2017"
7) "market": "Butha-Buthe","commodity": 55,"price": "65","month": "04","year": "2017"

是复制的，我想将它们合并，并使它们的平均价格值。

我试图使用reduce函数，但是我不知道如何识别重复的值，特别是如果它们没有排序的话。

我发布了代码，但这是无用的，因为我无法理解如何用reduce来识别重复代码：

​

var data = [
{"market": "Qacha's nek","commodity": 55,"price": "90","month": "04","year": "2017"}, 
{"market": "Mohales Hoek","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Mafeteng","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Maseru","commodity": 55,"price": "69","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "66","month": "04","year": "2017"}, 
{"market": "Leribe","commodity": 55,"price": "64","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "65","month": "04","year": "2017"}, 
{"market": "Thaba-Tseka","commodity": 55,"price": "82","month": "04","year": "2017"},
{"market": "Thaba-Tseka","commodity": 55,"price": "81","month": "04","year": "2017"},
{"market": "Maseru","commodity": 55,"price": "74,99","month": "04","year": "2017"}
];

var avg = data.reduce(function(result, current) {
			console.log(result,current);
      if(!result){
      	result=current;
      }
      else {
      	if(result.market==current.market){
        	console.log(current.market);
        }
      }
});

​

在这里，我正在尝试理解还原函数是如何工作的：https://jsfiddle.net/brainsengineering/7tmdx0kg/7/。

Answer 1

您可以为想要的属性获取一个组合键，并将price格式替换为数字可解析格式。

​

var data = [{ market: "Qacha's nek", commodity: 55, price: "90", month: "04", year: "2017" }, { market: "Mohales Hoek", commodity: 55, price: "75", month: "04", year: "2017" }, { market: "Mafeteng", commodity: 55, price: "75", month: "04", year: "2017" }, { market: "Maseru", commodity: 55, price: "69", month: "04", year: "2017" }, { market: "Butha-Buthe", commodity: 55, price: "66", month: "04", year: "2017" }, { market: "Leribe", commodity: 55, price: "64", month: "04", year: "2017" }, { market: "Butha-Buthe", commodity: 55, price: "65", month: "04", year: "2017" }, { market: "Thaba-Tseka", commodity: 55, price: "82", month: "04", year: "2017" }, { market: "Thaba-Tseka", commodity: 55, price: "81", month: "04", year: "2017" }, { market: "Maseru", commodity: 55, price: "74,99", month: "04", year: "2017" }],
    keys = ['market', 'commodity', 'month', 'year'],
    count = {},
    result = data.reduce(function (r, o) {
        var key = keys.map(function (k) { return o[k]; }).join('|');
        if (!count[key]) {
            count[key] = { sum: +o.price.replace(',', '.'), data: JSON.parse(JSON.stringify(o)) };
            count[key].data.count = 1;
            r.push(count[key].data);
        } else {
            count[key].sum += +o.price.replace(',', '.');
            count[key].data.price = (count[key].sum / ++count[key].data.count).toString();
        }
        return r;
    }, []);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

​

Answer 2

将每个项目的价格分组，将它们添加到reduce调用中的数组中。您可以跟踪在同一个函数中复制哪些项。然后使用重复项的循环来计算平均值。

注意，为了更容易地解析，我不得不将价格74,99更改为74.99。如果在用例中这是关键的话，您可能需要某种本地化/全球化库。

​

var data = [
{"market": "Qacha's nek","commodity": 55,"price": "90","month": "04","year": "2017"}, 
{"market": "Mohales Hoek","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Mafeteng","commodity": 55,"price": "75","month": "04","year": "2017"}, 
{"market": "Maseru","commodity": 55,"price": "69","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "66","month": "04","year": "2017"}, 
{"market": "Leribe","commodity": 55,"price": "64","month": "04","year": "2017"}, 
{"market": "Butha-Buthe","commodity": 55,"price": "65","month": "04","year": "2017"}, 
{"market": "Thaba-Tseka","commodity": 55,"price": "82","month": "04","year": "2017"},
{"market": "Thaba-Tseka","commodity": 55,"price": "81","month": "04","year": "2017"},
{"market": "Maseru","commodity": 55,"price": "74.99","month": "04","year": "2017"}
];

function parsePrice(str) {
  // TODO: localization
  return +str;
}

function formatPrice(num) {
  return num.toFixed(2);
}

function getHashKey(item) {
  return JSON.stringify([item.market, item.commodity, item.month, item.year]);
}

var duplicatedItems = {};
var prices = data.reduce(function(result, current) {
  var key = getHashKey(current);
  if (key in result) {
    result[key].push(parsePrice(current.price));
    duplicatedItems[key] = current;
  } else {
    result[key] = [parsePrice(current.price)];
  }
  return result;
}, {});
var avg = Object.keys(duplicatedItems).map(function(key) {
  var item = duplicatedItems[key];
  var avgPrice = prices[key].reduce(function(acc, price) { return acc + price; }, 0) / prices[key].length;
  return {
    market: item.market,
    commodity: item.commodity,
    price: formatPrice(avgPrice),
    month: item.month,
    year: item.year
  };
});

console.log(avg);

​

Answer 3

如果这些值已经存在，则可以将其插入新数组并进行合并：

 const result = [];

 outer: for(const {  market, commodity,  price, month, year } of input) {
    for(const other of result) {
       if(market === other.market && commodity === other.commodity && month === other.month && year === other.year) {
         other.prices.push(+price);

         continue outer;
       }
    }
    result.push({ market, commodity, prices: [+price], month, year });
 }

 for(const group of result)
   group.price = group.prices.reduce((a, b) => a + b, 0) / group.prices.length;