JSON DeserializeObject无法从System.String转换为模型

Question

我试图反序列化JSON，继续向我展示这个异常：

无法从System.String转换为SmartBookLibrary.ViewModel.BookJ1。 描述:在执行当前web请求时发生了未处理的异常。请查看堆栈跟踪以获得有关错误的更多信息，以及它起源于代码的位置。 异常详细信息: System.ArgumentException:无法从System.String转换为SmartBookLibrary.ViewModel.BookJ1。

下面是我的JSON示例：

{
  "authorfamily1": "von Goethe",
  "authorname1": "Johann",
  "authorsurname1": "Wolfgang",
  "title": "Fausto I",
  "extension": "epub",
  "md5": "58cb1dd438bc6c6027fcda9e7729e5ee",
  "isbn": "",
  "descr": "",
  "cover": "1"
},
{
  "authorfamily1": "von Goethe 1",
  "authorname1": "Johann",
  "authorsurname1": "Wolfgang",
  "title": "Fausto I",
  "extension": "epub",
  "md5": "58cb1dd438bc6c6027fcda9e7729e5ee",
  "isbn": "",
  "descr": "",
  "cover": "1"
}

以下是守则：

var json = System.IO.File.ReadAllText("/data1.json");           
var courses = JsonConvert.DeserializeObject<Dictionary<string, BookJ1>>(json);

下面是我的模型(VM)：

public class BookJ1
{
    public string title { get; set; }
    public string isbn { get; set; }
    public string extension { get; set; }
    public string authorfamily1 { get; set; }
    public string authorname1 { get; set; }
    public string md5 { get; set; }
    public int cover { get; set; }
    [AllowHtml]
    [Column(TypeName = "text")]
    public string descr { get; set; }
}

Answer 1

假设显示的示例是文件中的样子，

在试图反序列化JSON之前，您很可能需要将其格式化为数组

var data = System.IO.File.ReadAllText("/data1.json");
var json = string.Format("[{0}]", data);
BookJ1[] courses = JsonConvert.DeserializeObject<BookJ1[]>(json);

但是，如果显示的示例不完整，并且文件中的数据实际上存储为数组

[{
  "authorfamily1": "von Goethe",
  "authorname1": "Johann",
  "authorsurname1": "Wolfgang",
  "title": "Fausto I",
  "extension": "epub",
  "md5": "58cb1dd438bc6c6027fcda9e7729e5ee",
  "isbn": "",
  "descr": "",
  "cover": "1"
},
{
  "authorfamily1": "von Goethe 1",
  "authorname1": "Johann",
  "authorsurname1": "Wolfgang",
  "title": "Fausto I",
  "extension": "epub",
  "md5": "58cb1dd438bc6c6027fcda9e7729e5ee",
  "isbn": "",
  "descr": "",
  "cover": "1"
}]

然后只需要反序列化到正确的类型。

var json = System.IO.File.ReadAllText("/data1.json");           
BookJ1[] courses = JsonConvert.DeserializeObject<BookJ1[]>(json);