在处理完所有项之后,我无法调用OnComplete()方法。我需要这样做,以便(至少)隐藏加载视图。我对JavaRX有点陌生,所以我不知道问题到底在哪里。您能帮助我在处理所有项目时调用OnComplete()吗?
该守则做了以下工作:
守则如下:
private void loadDataRX(final long fromTime, final long toTime) {
mLoadingPb.setVisibility(View.VISIBLE);
iCompositeDisposable.clear();
iCompositeDisposable.add(mViewModel.getItems(fromTime, toTime)
.subscribeOn(Schedulers.io())
.flatMap(items -> {
Activity context = ItemFragment.this.getActivity();
if (context == null) {
Log.e(TAG, "Cannot present results: context is null");
return Flowable.empty();
} else {
context.runOnUiThread(() -> {
mItems.clear();
mCustomView.reset();
});
if (items != null && items.size() > 0) {
return Flowable.just(items);
} else {
Log.i(TAG, "No items.");
return Flowable.just(Collections.singletonList(new Item(-1))); // This is my current way of solving a similar problem so as to know if I don't have any items
}
}
})
.concatMapIterable(items -> items)
.concatMap(item -> {
if (item.getUid() == -1) {
return Flowable.just(item);
}
String file = item.getFileName();
boolean uploaded = item.isUploaded();
if (uploaded) { // Remote file
if (item.getUid() > 0) {
return iRetrofit.create(RestApi.class).getItem(item.getUid());
} else {
return Flowable.empty();
}
} else { // Local file
return Flowable.just(item);
}
})
.observeOn(AndroidSchedulers.mainThread())
.subscribe(item -> {
Log.i(TAG, "Loaded items RX");
if (item instanceof Item) {
//Do stuff with the item and the files
} else if (item instanceof ResponseBody) {
//This is dirty but I didn't find another way. So here I basically extract the items and the files from the server's response. At least, it works.
} else {
Log.i(TAG, "No results for the given dates");
}
}, throwable -> {
mLoadingPb.setVisibility(View.GONE);
Log.e(TAG, "Error: " + throwable.getMessage());
}, () -> {
mLoadingPb.setVisibility(View.GONE);
Log.i(TAG, "Loading results completed"); // Can't get this to be called
})
);
}提前谢谢。
发布于 2019-03-03 15:50:04
我猜mViewModel.getItems会返回Flowable。为了实现可流动,我们需要显式地处理它。
要解决这个问题,可以让mViewModel.getItems返回Single<List<ItemType>>,然后使用.flatMapObservable { Observable.fromIterable(it) }转换流来处理每个项。
https://stackoverflow.com/questions/54964009
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