Laravel-5.6‘类’在地点和地点选择

Question

我使用这个查询并得到一个错误：

$description = $request->get('description');
                $description_query = Transcationhistorique::where(function ($query) use ($description, $user_id) {
                    $query->where('receiver_id', $user_id,'description', 'LIKE','%' . $description . '%')
                        ->orWhere('description', 'LIKE','%' . $description . '%','sender_id', $user_id);
                })->get();

这就是我得到的错误：

"SQLSTATE42S22:未找到列：'where子句‘1054个未知列'0’(sender_id = 32和0 = %salaire%和1 = LIKE和2 = description)或receiver_id =32)

我真正想要的是：

select * from `transcation_historique` where (`sender_id` = 32 and `description` = %salaire%) or (`receiver_id` = 32 and `description` = %salaire%)

Answer 1

你应该试试这个：

$description = $request->get('description');
$query = Transcationhistorique::where(function ($query) use ($description, $user_id) {
      $query->where('receiver_id', $user_id)
          ->where('description', 'LIKE','%' . $description . '%');
})
->orWhere(function ($query) use ($description, $user_id) {
      $query->where('sender_id', $user_id)
          ->where('description', 'LIKE','%' . $description . '%');
})
->get();

Answer 2

尝尝这个

Transcationhistorique::where(function ($query) use ($description, $user_id) {
            $query->where(['receiver_id' => $user_id, 'description' => 'LIKE %' . $description . '%'])
                ->orWhere(['description' => 'LIKE %' . $description . '%', 'sender_id' => $user_id]);
        })->get();

Answer 3

然后，您应该使用以下语句：

$query = Transcationhistorique::where(function ($query) use ($description, $user_id) {
      $query->where('receiver_id', $user_id)
          ->where('description', 'LIKE','%' . $description . '%');
})
->orWhere(function ($query) use ($description, $user_id) {
      $query->where('sender_id', $user_id)
          ->where('description', 'LIKE','%' . $description . '%');
})
->get();