在编码参数中解码url (returnUrl)

Question

我希望使用倍数乘以参数returnUrl来检索url中的一些参数。

示例：

HTTPS://force.com?positionId=a0w0X000007HjBuQAK&lang=fr&mediaChannel=a0o0X00000EGQ5TQAX&returnUrl=https%253A%2F%2force.com%2Fcxsrec__cxsSearchDetail%3Fid%3Da0w0X000007HjBuQAK%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX%26returnUrl%3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526 site%253DFrance%2526hcFilter%253Da0Z0X00000XiFF3UAN%252Ca0Z0X00000XiUqTUAV%2526orderBy%253DPosition_name__c%2526orderDir%253Dasc%2526mediaChannel%253Da0o0X00000EGQ5TQAX%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX’

?...returnUrl%3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526site%253DFrance%2526hcFilter...

我想得到参数site的值。

我尝试使用decodeURI函数，然后使用decodeURI，但在returnUrl之后没有解码参数。

还有其他功能可以这样做吗？

Answer 1

你需要decodeURIComponent()。

我在URL中删除了site前的一个空格：

const url1 = new URL('https://force.com?positionId=a0w0X000007HjBuQAK&lang=fr&mediaChannel=a0o0X00000EGQ5TQAX&returnUrl=https%253A%2F%2force.com%2Fcxsrec__cxsSearchDetail%3Fid%3Da0w0X000007HjBuQAK%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX%26returnUrl%3Dhttps%253A%2F%2force.com%2Fcxsrec__cxsSearch%253Flang%253Dfr%2526mediaChannel%253Da0o0X00000EGQ5TQA%2526site%253DFrance%2526hcFilter%253Da0Z0X00000XiFF3UAN%252Ca0Z0X00000XiUqTUAV%2526orderBy%253DPosition_name__c%2526orderDir%253Dasc%2526mediaChannel%253Da0o0X00000EGQ5TQAX%26lang%3Dfr%26mediaChannel%3Da0o0X00000EGQ5TQAX');
const params1 = new URLSearchParams(url1.search);
const returnUrl = params1.get('returnUrl');

const url2 = new URL(decodeURIComponent(returnUrl));
const params2 = new URLSearchParams(url2.search);
const site = params2.get('site');

console.log(site);

参见 description中的一些详细信息