我需要在集群中运行一些作业,一次只能运行一个作业。因为我的团队使用Hazelcast,所以我最终得到了一个基于Hazelcast ILock实现的解决方案。为了这个问题的目的,我将对此作一个概括。让我们假设我们有以下接口(这些接口可以很容易地实现,例如,由Hazelcast或Reddison (Redis)实现):
public interface MyDistributedLock {
boolean lock();
void unlock();
boolean isLockedByCurrentThread();
}
public interface MyLockDistributedFactory {
MyDistributedLock getLock(String name);
}如果无法获得锁,则锁方法等待:
private Mono<Void> lock(String name, Publisher<?> publisher, MyLockDistributedFactory myLockFactory) {
// important to release lock on the same thread as
// it was aquired
Scheduler scheduler = Schedulers.newSingle(name.toLowerCase());
return Mono.defer(() -> Mono.just(myLockFactory.getLock(name)))
publishOn(scheduler)
.doOnNext(MyDistributedLock::lock)
.doOnNext(lock -> LOGGER.info("Process acquired lock for resource {}", name))
.flatMapMany(lock -> Flux.from(publisher))
.publishOn(scheduler)
.doFinally(signalType -> {
MyDistributedLock lock = myLockFactory.getLock(name);
if (signalType == SignalType.CANCEL) {
// cancel ignores publishOn
scheduler.schedule(() -> {
lock.unlock();
LOGGER.info("Process released lock for resource {} due to signal type {}", name, signalType);
});
} else if (lock.isLockedByCurrentThread()) {
lock.unlock();
LOGGER.info("Process released lock for resource {} due to signal type {}", name, signalType);
}
})
.then();
}和一些工作的例子
private Mono<Void> someJobRunEveryOneHourOnEveryNodeInCluster() {
MyLockDistributedFactory hazelcast = ...;
return lock("some-job", Flux.just(1,2), hazelcast)
.repeatWhen(afterOneHour());
}我不知道这是一种使用项目反应堆的好方法(以及正确的实现),还是应该以另一种方式进行。请指点。
发布于 2019-01-28 15:54:54
当使用反应堆时,这是一种正确的方法,因为您负责将阻塞部分抵消到专用的Scheduler/Thread中。
但我要说的是,这样的互斥代码一般不太适合于反应式编程:您失去了使用较少的线程进行更多操作的关键好处之一,如果忘记使用专用线程publishOn,则可能会阻塞应用程序的其他部分,等等……
https://stackoverflow.com/questions/54377145
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