我正在为一个处理电路的作业编写一个剪辑程序。我使用Protege创建了我的本体,并从那里创建了clp文件并将其加载到剪辑中。结果如下:
(defclass systemEntity
(is-a USER)
(role abstract)
(single-slot suspect
(type SYMBOL)
(allowed-values yes no)
(default no)
(create-accessor read-write))
(single-slot out
(type INTEGER)
(range 0 31)
(create-accessor read-write)))
(defclass command
(is-a systemEntity)
(role concrete))
(defclass component
(is-a systemEntity)
(role abstract))
(defclass sensor
(is-a component)
(role concrete)
(single-slot theoretical
(type INTEGER)
(create-accessor read-write))
(single-slot out
(type INTEGER)
(range 0 31)
(create-accessor read-write))
(single-slot reading
(type INTEGER)
(range 0 31)
(create-accessor read-write))
(single-slot input
(type INSTANCE)
(allowed-classes internal-component)
(create-accessor read-write)))
(defclass internal-component
(is-a component)
(role concrete)
(single-slot short-out
(type INTEGER)
(range 0 0)
(default 0)
(create-accessor read-write))
(multislot output
(type INSTANCE)
(allowed-classes component)
(create-accessor read-write))
(single-slot msb-out
(type INTEGER)
(range 0 15)
(create-accessor read-write))
(single-slot input2
(type INSTANCE)
(allowed-classes systemEntity)
(create-accessor read-write))
(single-slot input1
(type INSTANCE)
(allowed-classes systemEntity)
(create-accessor read-write)))
(defclass adder
(is-a internal-component)
(role concrete))
(defclass multiplier
(is-a internal-component)
(role concrete))
(defclass circuit
(is-a systemEntity)
(role concrete)
(multislot outputs
(type INSTANCE)
(allowed-classes sensor)
(create-accessor read-write))
(multislot has-components
(type INSTANCE)
(allowed-classes component)
(create-accessor read-write))
(multislot inputs
(type INSTANCE)
(allowed-classes command)
(create-accessor read-write)))
(defclass data
(is-a USER)
(role abstract)
(single-slot clock
(type INTEGER)
(range 1 ?VARIABLE)
(create-accessor read-write))
(single-slot object
(type INSTANCE)
(allowed-classes systemEntity)
(create-accessor read-write))
(single-slot value
(type INTEGER)
(create-accessor read-write)))
(defclass command_data
(is-a data)
(role concrete)
(single-slot object
(type INSTANCE)
(allowed-classes command)
(create-accessor read-write)))
(defclass reading_data
(is-a data)
(role concrete)
(single-slot object
(type INSTANCE)
(allowed-classes sensor)
(create-accessor read-write)))
(definstances facts
([a1] of adder
(input1 [input_1])
(input2 [input_1])
(output
[m1]
[p1])
(short-out 0)
(suspect no))
([a2] of adder
(input1 [p1])
(input2 [p2])
(output [out1])
(short-out 0)
(suspect no))
([circuit_1] of circuit
(has-components
[m1]
[m2]
[m3]
[out1]
[a1]
[a2]
[p1]
[p2])
(inputs
[input_1]
[input_2]
[input_3]
[input_4])
(outputs [out1])
(suspect no))
([command_1_inp1] of command_data
(clock 1)
(object [input_1])
(value 21))
([command_1_inp2] of command_data
(clock 1)
(object [input_2])
(value 28))
([command_1_inp3] of command_data
(clock 1)
(object [input_3])
(value 10))
([command_1_inp4] of command_data
(clock 1)
(object [input_4])
(value 25))
([input_1] of command
(suspect no))
([input_2] of command
(suspect no))
([input_3] of command
(suspect no))
([input_4] of command
(suspect no))
([m1] of sensor
(input [a1])
(suspect no))
([m2] of sensor
(input [p1])
(suspect no))
([m3] of sensor
(input [p2])
(suspect no))
([out1] of sensor
(input [a2])
(suspect no))
([p1] of multiplier
(input1 [input_2])
(input2 [a1])
(output
[m2]
[a2])
(short-out 0)
(suspect no))
([p2] of multiplier
(input1 [input_3])
(input2 [input_4])
(output
[m3]
[a2])
(short-out 0)
(suspect no))
([reading_1_m1] of reading_data
(clock 1)
(object [m1])
(value 10))
([reading_1_m2] of reading_data
(clock 1)
(object [m2])
(value 24))
([reading_1_m3] of reading_data
(clock 1)
(object [m3])
(value 26))
([reading_1_out] of reading_data
(clock 1)
(object [out1])
(value 18))
)我试图弄清楚如何使缺陷规则打印出所有的输入和输出,从一个类的一个特定的等价比,如加法器a1。我将通过展示以下几个定义来说明我的意思:
([a1] of adder
(input1 [input_1])
(input2 [input_1])
(output
[m1]
[p1])
(short-out 0)
(suspect no))a1加法器以input1和input2作为input_1实例,即:
([command_1_inp1] of command_data
(clock 1)
(object [input_1])
(value 21))以及输出到m1和p1,m1实例可以从它们获得输出,即:
([reading_1_m1] of reading_data
(clock 1)
(object [m1])
(value 10)) 但是,当我试图访问实例的值(例如,第一个输入)时,我会得到一个错误No object of existing classes can satisfy is-a restriction in object pattern.
(defrule find-input-1
(object (is-a command_data)
(clock ?clock)
(value ?value))
=>
(printout t ?clock " " ?value crlf))我做错了什么?如何访问实例所具有的值?
发布于 2019-01-17 23:44:12
您需要在您的规则中使用对象关键字,否则CLIPS将内部组件视为一个缺陷模板事实。
(defrule print-sensor
(object (is-a internal-component) (input1 ?input1) (input2 ?input2))
=>
(printout t ?input1 " " ?input2 crlf))您还需要将内部组件类声明为反应性类,以便在规则中使用它。
(defclass internal-component
(is-a component)
(role concrete)
(pattern-match reactive)
.
.
.
)https://stackoverflow.com/questions/54245594
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