我一直试图找出如何使用自定义模型绑定到.net Core2WebAPI,但一直未能使它发挥作用。
我读过一些文章,如下所示:http://www.palmmedia.de/Blog/2018/5/13/aspnet-core-model-binding-of-abstract-classes Asp net core rc2. Abstract class model binding
在我的例子中,bindingContext.ModelName总是空的。有人能解释为什么会这样吗?
下面的示例实现
控制器
public IActionResult SomeAction([ModelBinder(BinderType = typeof(BlahTypeModelBinder))][FromBody]TheBaseClass theBase)
{
return Ok();
}模型
public abstract class TheBaseClass
{
public abstract int WhatType { get; }
}
public class A : TheBaseClass
{
public override int WhatType { get { return 1; } }
}
public class B : TheBaseClass
{
public override int WhatType { get { return 2; } }
}提供程序
public class BhalTypeBinderProvider : IModelBinderProvider
{
public IModelBinder GetBinder(ModelBinderProviderContext context)
{
if (context == null)
throw new ArgumentNullException(nameof(context));
if (context.Metadata.ModelType == typeof(TheBaseClass))
{
var assembly = typeof(TheBaseClass).Assembly;
var abstractSearchClasses = assembly.GetExportedTypes()
.Where(t => t.BaseType.Equals(typeof(TheBaseClass)))
.Where(t => !t.IsAbstract)
.ToList();
var modelBuilderByType = new Dictionary<Type, Microsoft.AspNetCore.Mvc.ModelBinding.Binders.ComplexTypeModelBinder>();
foreach (var type in abstractSearchClasses)
{
var propertyBinders = new Dictionary<ModelMetadata, IModelBinder>();
var metadata = context.MetadataProvider.GetMetadataForType(type);
foreach (var property in metadata.Properties)
{
propertyBinders.Add(property, context.CreateBinder(property));
}
modelBuilderByType.Add(type, new Microsoft.AspNetCore.Mvc.ModelBinding.Binders.ComplexTypeModelBinder(propertyBinders));
}
return new BlahTypeModelBinder(modelBuilderByType, context.MetadataProvider);
}
return null;
}
}粘结剂
public class BlahTypeModelBinder : IModelBinder
{
private readonly IModelMetadataProvider _metadataProvider;
private readonly IDictionary<Type, Microsoft.AspNetCore.Mvc.ModelBinding.Binders.ComplexTypeModelBinder> _binders;
public BlahTypeModelBinder(IDictionary<Type, Microsoft.AspNetCore.Mvc.ModelBinding.Binders.ComplexTypeModelBinder> binders, IModelMetadataProvider metadataProvider)
{
_metadataProvider = metadataProvider;
_binders = binders;
}
public Task BindModelAsync(ModelBindingContext bindingContext)
{
if (bindingContext == null)
throw new ArgumentNullException(nameof(bindingContext));
var modelTypeValue = bindingContext.ValueProvider.GetValue(ModelNames.CreatePropertyModelName(bindingContext.ModelName, "WhatType"));
if (modelTypeValue != null && modelTypeValue.FirstValue != null)
{
Type modelType = Type.GetType(modelTypeValue.FirstValue);
if (this._binders.TryGetValue(modelType, out var modelBinder))
{
ModelBindingContext innerModelBindingContext = DefaultModelBindingContext.CreateBindingContext(
bindingContext.ActionContext,
bindingContext.ValueProvider,
this._metadataProvider.GetMetadataForType(modelType),
null,
bindingContext.ModelName);
/*modelBinder*/
this._binders.First().Value.BindModelAsync(innerModelBindingContext);
bindingContext.Result = innerModelBindingContext.Result;
return Task.CompletedTask;
}
}
//More code
}
}发布于 2019-01-14 22:37:38
我终于设法解决了这个问题。你不需要提供者。只是下面的活页夹起作用
public class BlahTypeModelBinder : IModelBinder
{
public Task BindModelAsync(ModelBindingContext bindingContext)
{
if (bindingContext == null)
throw new ArgumentNullException(nameof(bindingContext));
var json = ExtractRequestJson(bindingContext.ActionContext);
var jObject = Newtonsoft.Json.Linq.JObject.Parse(json);
var whatTypeInt = (int)jObject.SelectToken("WhatType");
if (whatTypeInt == 1)
{
var obj = DeserializeObject<A>(json);
bindingContext.Result = ModelBindingResult.Success(obj);
}
else if (whatTypeInt == 2)
{
var obj = DeserializeObject<B>(json);
bindingContext.Result = ModelBindingResult.Success(obj);
}
else
{
bindingContext.Result = ModelBindingResult.Failed();
return Task.CompletedTask;
}
return Task.CompletedTask;
}
private static string ExtractRequestJson(ActionContext actionContext)
{
var content = actionContext.HttpContext.Request.Body;
return new StreamReader(content).ReadToEnd();
}
private static T DeserializeObject<T>(string json)
{
return Newtonsoft.Json.JsonConvert.DeserializeObject<T>(json, new Newtonsoft.Json.JsonSerializerSettings
{
TypeNameHandling = Newtonsoft.Json.TypeNameHandling.Auto
});
}
}发布于 2019-01-12 17:59:58
链接以使用外部查询字符串参数确定类型的示例。
如果您的调用您的操作,如:SomeAction?WhatType=YourNamespaceName.A,则绑定将按预期的方式工作。
bindingContext.ModelName是空的很好,它将在模型绑定之后设置。如果需要,可以在设置bindingContext.Result之后设置它。参数WhatType来自于QueryStringValueProvider,所以没有前缀是可以的。
如何单独完成基于JSON的抽象模型绑定
为此,我们需要:
Type-s的一些反射。1. ValueProvider
这里有一篇关于创建ValueProviders的详细文章:
作为起点,这里有一些代码成功地从正文json中提取WhatType整数:
public class BlahValueProvider : IValueProvider
{
private readonly string _requestBody;
public BlahValueProvider(string requestBody)
{
_requestBody = requestBody;
}
private const string PROPERTY_NAME = "WhatType";
public bool ContainsPrefix(string prefix)
{
return prefix == PROPERTY_NAME;
}
public ValueProviderResult GetValue(string key)
{
if (key != PROPERTY_NAME)
return ValueProviderResult.None;
// parse json
try
{
var json = JObject.Parse(_requestBody);
return new ValueProviderResult(json.Value<int>("WhatType").ToString());
}
catch (Exception e)
{
// TODO: error handling
throw;
}
}
}
public class BlahValueProviderFactory : IValueProviderFactory
{
public Task CreateValueProviderAsync(ValueProviderFactoryContext context)
{
if (context == null)
{
throw new ArgumentNullException(nameof(context));
}
var request = context.ActionContext.HttpContext.Request;
if (request.ContentType == "application/json")
{
return AddValueProviderAsync(context);
}
return Task.CompletedTask;
}
private Task AddValueProviderAsync(ValueProviderFactoryContext context)
{
using (StreamReader sr = new StreamReader(context.ActionContext.HttpContext.Request.Body))
{
string bodyString = sr.ReadToEnd();
context.ValueProviders.Add(new BlahValueProvider(bodyString));
}
return Task.CompletedTask;
}
}当然,,您必须在Startup.cs中注册这个工厂,就像您注册模型活页夹一样。这绝对没有将提取的数字转换为实际的类型(关于这个问题,请参见下面的第2点),但是如果在您的行上放置一个断点与if (modelTypeValue != null一起看,您可以看到,即使没有单独的GET参数,modelTypeValue也在您的身边。
2.反思
请注意,您正在尝试根据一个在现有实例上动态计算的属性(它们不是静态的)来确定类型。虽然通过了解当前的实现,我知道这是可能的(创建模型的空实例,检查WhatType属性,丢弃实例),但这是非常糟糕的做法,因为没有什么可以保证实例属性是静态不变的。
这个干净的解决方案将是一个属性,它包含该类的WhatType编号。然后我们可以考虑这个属性并构建一个映射,将ints映射到Types,如果这个问题超出了范围,但是如果您不熟悉的话,可以查找任何自定义属性教程,并且您将能够非常快地将它组合在一起。
https://stackoverflow.com/questions/54079310
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