使用xslt-3重新构造xml，如果记录具有特定元素，则将其拆分为多个记录。

Question

考虑到下面的xml文件，我只需要选择那些有<marc:datafield tag="911"的记录，并且从每个911中只提取出代码h或j：<marc:subfield code="h">或<marc:subfield code="j">的元素。两者都可以有文本值，即数字和文本。然后更改所选的记录和元素，因此我们将001值保留为RECNO，并从1开始添加记录ID的唯一增量值。如果h或j不存在，则记录没有相应的元素。Name_1是`的新元素名，Name_2是的新元素名

<?xml version="1.0" encoding="UTF-8" ?>
<marc:collection
    xmlns:marc="http://www.loc.gov/MARC21/slim"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.loc.gov/MARC21/slim http://www.loc.gov/standards/marcxml/schema/MARC21slim.xsd">
    <marc:record>
        <marc:controlfield tag="001">7</marc:controlfield>
        </marc:datafield>
        <marc:datafield tag="911" ind1=" " ind2=" ">
            <marc:subfield code="o">KEN</marc:subfield>
            <marc:subfield code="b">MAIN</marc:subfield>
            <marc:subfield code="e">20171027</marc:subfield>
            <marc:subfield code="n">V.6</marc:subfield>
            <marc:subfield code="d">001000000918</marc:subfield>
            <marc:subfield code="a">001000000918</marc:subfield>
            <marc:subfield code="h">v.1</marc:subfield>
            <marc:subfield code="j">1686</marc:subfield>
        </marc:datafield>
        <marc:datafield tag="911" ind1=" " ind2=" ">
            <marc:subfield code="o">KEN</marc:subfield>
            <marc:subfield code="b">MAIN</marc:subfield>
            <marc:subfield code="e">20171027</marc:subfield>
            <marc:subfield code="n">V.6</marc:subfield>
            <marc:subfield code="d">001000000921</marc:subfield>
            <marc:subfield code="a">001000000921</marc:subfield>
            <marc:subfield code="h">v.2</marc:subfield>
            <marc:subfield code="j">1687</marc:subfield>
        </marc:datafield>
        <marc:datafield tag="911" ind1=" " ind2=" ">
            <marc:subfield code="o">KEN</marc:subfield>
            <marc:subfield code="b">MAIN</marc:subfield>
            <marc:subfield code="e">20171027</marc:subfield>
            <marc:subfield code="n">V.6</marc:subfield>
            <marc:subfield code="d">001000000920</marc:subfield>
            <marc:subfield code="a">001000000920</marc:subfield>
            <marc:subfield code="h">v.2</marc:subfield>
            <marc:subfield code="j">1687</marc:subfield>
        </marc:datafield>
        <marc:datafield tag="911" ind1=" " ind2=" ">
            <marc:subfield code="o">KEN</marc:subfield>
            <marc:subfield code="b">MAIN</marc:subfield>
            <marc:subfield code="e">20171027</marc:subfield>
            <marc:subfield code="n">V.6</marc:subfield>
            <marc:subfield code="d">001000000919</marc:subfield>
            <marc:subfield code="a">001000000919</marc:subfield>
            <marc:subfield code="h">v.1</marc:subfield>
            <marc:subfield code="j">1686</marc:subfield>
        </marc:datafield>
    </marc:record>
    <marc:record>
    <marc:controlfield tag="001">12481</marc:controlfield>
    <marc:datafield tag="911" ind1=" " ind2=" ">
        <marc:subfield code="o">KEN</marc:subfield>
        <marc:subfield code="b">MAIN</marc:subfield>
        <marc:subfield code="e">20160324</marc:subfield>
        <marc:subfield code="n">II.5</marc:subfield>
        <marc:subfield code="d">061000019180</marc:subfield>
        <marc:subfield code="a">061000019180</marc:subfield>
        <marc:subfield code="h">v.5</marc:subfield>
    </marc:datafield>
    <marc:datafield tag="911" ind1=" " ind2=" ">
        <marc:subfield code="o">KEN</marc:subfield>
        <marc:subfield code="b">MAIN</marc:subfield>
        <marc:subfield code="e">20160324</marc:subfield>
        <marc:subfield code="n">II.5</marc:subfield>
        <marc:subfield code="d">061000019181</marc:subfield>
        <marc:subfield code="a">061000019181</marc:subfield>
        <marc:subfield code="h">v.4</marc:subfield>
    </marc:datafield>
</marc:record>
<marc:record>
    <marc:controlfield tag="001">1</marc:controlfield>
</marc:record>
</marc:collection>

预期产出：

<?xml version="1.0" encoding="UTF-8" ?>
<marc:collection
    xmlns:marc="http://www.loc.gov/MARC21/slim"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.loc.gov/MARC21/slim http://www.loc.gov/standards/marcxml/schema/MARC21slim.xsd">
    <RECORD ID="1">   
        <RECNO>7</RECNO>
        <NAME_1>v.1</NAME_1>
        <NAME_2>1686</NAME_2>
        </RECORD>
        <RECORD ID="2">
            <RECNO>7</RECNO>
            <NAME_1>v.2</NAME_1>
            <NAME_2>1687</NAME_2>
        </RECORD>
        <RECORD ID="3">
            <RECNO>7</RECNO>
            <NAME_1>v.2</NAME_1>
            <NAME_2>1687</NAME_2>
        </RECORD>
        <RECORD ID="4">
            <RECNO>7</RECNO>
            <NAME_1>v.4</NAME_1>
            <NAME_2>16887</NAME_2>
        </RECORD>
        <RECORD ID="5">
            <RECNO>12481</RECNO>
            <NAME_1>v.5</NAME_1>
        </RECORD>
    <RECORD ID="6">
            <RECNO>12481</RECNO>
            <NAME_1>v.4</NAME_1>
        </RECORD>
</marc:collection>

如何使用xslt-3实现上述结果？(Saxon 9.8 HE)

Answer 1

我没有看到任何真正的分裂，您似乎只是想将record/datafield[subfield/@code = ('h', 'j')]元素映射到RECORD元素，然后将subfield元素映射到NAME_1/NAME_2元素：

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema"
    xpath-default-namespace="http://www.loc.gov/MARC21/slim"
    expand-text="yes"
    exclude-result-prefixes="#all"
    version="3.0">

  <xsl:output indent="yes"/>

  <xsl:template match="/*">
      <xsl:copy>
          <xsl:copy-of select="@*"/>
          <xsl:apply-templates select="record/datafield[subfield/@code = ('h', 'j')]"/>
      </xsl:copy>
  </xsl:template>

  <xsl:template match="datafield">
      <RECORD ID="{position()}">
          <RECNO>{ancestor::record/controlfield}</RECNO>
          <xsl:apply-templates select="subfield[@code = ('h', 'j')]"/>
      </RECORD>
  </xsl:template>

  <xsl:template match="subfield[@code = 'h']">
      <NAME_1>{.}</NAME_1>
  </xsl:template>

  <xsl:template match="subfield[@code = 'j']">
      <NAME_2>{.}</NAME_2>
  </xsl:template>

</xsl:stylesheet>

https://xsltfiddle.liberty-development.net/bdxtrh