Java最终项目动物监测系统

Question

好的，我已经在这个Java类中为我的最后一个项目构建了这个代码。所发出的指示如下：

备选方案2:作为动物园管理员的监测系统，了解你所照料的动物的活动并监测它们的生存环境是很重要的。创建一个执行以下所有操作的监视系统： 询问用户是否希望监视动物，监视栖息地，或退出显示动物/生境选项列表(基于先前的选择)，这些选项从动物或生境文件中读取。 要求用户输入其中一个选项。

• 通过在文件中找到适当的部分来显示监视信息。
• 按类别和选择分隔各部分(如“动物-狮子”或“生境-Penguin”)
• 如果监视器检测到超出正常范围的东西，则使用对话框通知动物园管理员(这些将在文件中以*开始的新行表示)。不要在对话框中显示星号。)
• 允许用户返回原始选项。

我开发的代码如下：

import java.util.Scanner;



public class Final {


static final Scanner scan = new Scanner(System.in);


public static void main(String args[]) {

    System.out.println("Menu:");

    System.out.println("Monitor Animal");

    System.out.println("Monitor Habitat");

    System.out.println("Exit");



Scanner input1 = new Scanner(System.in);

String userInput1 = input1.nextLine();



    if (userInput1.equals("Monitor Animal")); {

        System.out.println("Details on lions");

        System.out.println("Details on tigars");

        System.out.println("Details on bears");

        System.out.println("Details on giraffes");

        System.out.println("Exit");



        Scanner input2 = new Scanner(System.in);

        String userInput2 = input2.nextLine();



        switch(userInput2) {

            case 1: userInput2 = "Details on lions";

                System.out.println("Animal - Lion");

                System.out.println("Name: Leo");

                System.out.println("Age: 5");

                System.out.println("Health concerns: Cut on left front paw");

                System.out.println("Feeding schedule: Twice daily");

                break;



            case 2: userInput2 = "Details on tigers";

                System.out.println("Animal - Tigar");

                System.out.println("Name: Maj");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: 3x daily");

                break;



            case 3: userInput2 = "Details on bears";

                System.out.println("Animal - Bear");

                System.out.println("Name: Baloo");

                System.out.println("Age: 1");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: None on record");

                break;



            case 4: userInput2 = "Details on giraffes";

                System.out.println("Animal - Giraffe");

                System.out.println("Name: Spots");

                System.out.println("Age: 12");

                System.out.println("Health concerns: None");

                System.out.println("Feeding schedule: Grazing");

                break;



            case 5: userInput2 = "Exit";

                break;



            default: userInput2 = System.out.println("Error: Invalid Animal");

                break;

            }



    if (userInput1.equals("Monitor Habitat")); {

        System.out.println("Details on penguin habitat");

        System.out.println("Details on bird house");

        System.out.println("Details on aquarium");

        System.out.println("Exit");



        Scanner input3 = new Scanner(System.in);

        String userInput3 = input3.nextLine();



        switch(userInput3) {



            case 1: userInput3 = "Details on penguin habitat";

                System.out.println("Habitat - Penguin");

                System.out.println("Temperature: Freezing");

                System.out.println("Food source: Fish in water running low");

                System.out.println("Cleanliness: Passed");

                break;



            case 2: userInput3 = "Details on bird house";

                System.out.println("Habitat - Bird");

                System.out.println("Temperature: Moderate");

                System.out.println("Food source: Natural from environment");

                System.out.println("Cleanliness: Passed");

                break;



            case 3: userInput3 = "Details on aquarium";

                System.out.println("Habitat - Aquarium");

                System.out.println("Temperature: Varies with output temperature");

                System.out.println("Food source: Added daily");

                System.out.println("Cleanliness: Needs cleaning from algae");

                break;



            case 4: userInput3 = "Exit";

                break;



            default: System.out.println("Error: Invalid Habitat");

                break;
    }



    if (userInput1.equals("Exit")); {

        System.out.println("Goodbye!");


    }

  }
}

它不会编译，我也不知道我做错了什么。有更好的方法吗？我已经试了一天半了，现在大约三个小时后就要到期了。任何帮助都将不胜感激！

Answer 1

if-语句的格式是错误的.不要在表达式之后提供分号。它应该在形式上

 if(expression){
 //statement

 }

Answer 2

在switch语句中，您将int与字符串进行比较。所以，您应该比较一个字符串和一个字符串。例如，在您的代码中：

Scanner input2 = new Scanner(System.in);
    String userInput2 = input2.nextLine();
    switch(userInput2) {

        case "Details on lions":
            System.out.println("Animal - Lion");
            System.out.println("Name: Leo");
            System.out.println("Age: 5");
            System.out.println("Health concerns: Cut on left front paw");
            System.out.println("Feeding schedule: Twice daily");
            break;

Answer 3

if(例如)上没有分号；

只是打字

if(){ 
} // simple as that. 

你的开关箱也有问题。需要

 case 'Details on penguin habitat':
 break;

 case 'Details on bird house':
 break