ReactStrap句柄输入隐式提交

Question

每当我在输入文本框上按Enter键时，输入元素中的隐式提交就会触发提交并重新加载页面：

import React, { Component } from "react";
import { Col, Button, Form, FormGroup, Label, Input } from "reactstrap";
import "./SearchBar.css";

class SearchBar extends Component {
constructor(props) {
    super(props);
    this.state = {
      term: ""
    };

    this.handleTermChange = this.handleTermChange.bind(this);
    this.handleSearch = this.handleSearch.bind(this);
    this.handleEnter = this.handleEnter.bind(this);
}

handleTermChange(e) {
    this.setState({ term: e.target.value });
}

handleSearch() {
    this.props.searchEngine(this.state.term);
}

handleEnter(e) {
    if (e.key === 13) {
      this.handleSearch();
    }
}

render() {
    return (
    <Form className="searchbox">
        <FormGroup row>
        <Label for="searchId" sm={2}>
            Search Engine
        </Label>
        <Col sm={10}>
            <Input
            type="text"
            placeholder="Enter Sth"
            onChange={this.handleTermChange}
            onKeyDown={this.handleEnter}
            />
        </Col>
        </FormGroup>

        <FormGroup>
        <Col sm="2">
            <div className="">
            <Button
                onClick={this.handleSearch}
                className="btn"
            >
                Submit
            </Button>
            </div>
        </Col>
        </FormGroup>
    </Form>
    );
}
}

export default SearchBar;

我只想像上面那样使用处理程序触发搜索函数，但避免隐式提交，即单击Submit按钮时使用相同的函数。否则，它只是重新加载页面并清除返回的结果。

我做错什么了？我以前没有经历过类似的问题。

依赖关系：

• “反应带”："^6.5.0“
• “引导”："^4.1.3“
• “反应”："^16.6.3“
• “反应”："^16.6.3“
• “react脚本”："2.1.1“

Answer 1

我发现触发隐式提交的是<Form>元素。我将其更改为<Form className="searchbox" onSubmit={this.handleSubmit}>并添加一个新函数：

handleSubmit(e) { 
    e.preventDefault(); 
    this.handleSearch();
}

根据问题修改的完整工作代码：

import React, { Component } from "react";
import { Col, Button, Form, FormGroup, Label, Input } from "reactstrap";
import "./SearchBar.css";

class SearchBar extends Component {
constructor(props) {
    super(props);
        this.state = {
            term: ""
        };

    this.handleTermChange = this.handleTermChange.bind(this);
    this.handleSearch = this.handleSearch.bind(this);
    this.handleEnter = this.handleEnter.bind(this);
    this.handleSubmit = this.handleSubmit.bind(this);
    }

    handleTermChange(e) {
        this.setState({ term: e.target.value });
    }

    handleSearch() {
        this.props.searchEngine(this.state.term);
    }

    handleEnter(e) {
        if (e.key === 13) {
        this.handleSearch();
        }
    }

    handleSubmit(e) {
        e.preventDefault();
        this.handleSearch();
   }

render() {
    return (
    <Form className="searchbox" onSubmit={this.handleSubmit}>
        <FormGroup row>
        <Label for="searchId" sm={2}>
            Search Engine
        </Label>
        <Col sm={10}>
            <Input
            type="text"
            placeholder="Enter Sth"
            onChange={this.handleTermChange}
            onKeyDown={this.handleEnter}
            />
        </Col>
        </FormGroup>

        <FormGroup>
        <Col sm="2">
            <div className="">
            <Button
                onClick={this.handleSearch}
                className="btn"
            >
                Submit
            </Button>
            </div>
        </Col>
        </FormGroup>
    </Form>
    );
}
}

export default SearchBar;

Answer 2

当Enter键按下时，您需要防止默认事件。

handleEnter(e) {
    if (e.key === 13) {
     e.preventDefault();
     this.handleSearch();
    }
}

e.preventDefault()告诉用户代理，如果事件没有被显式处理，那么它的默认操作就不应该像通常那样进行。