查询并不总是简单的,有时我需要创建一个纯SQL查询,查询生成器也不适合。ПрииспользованииDB::选择,подготовливаютсялипеременные,которыеподставленывзапрос?
在这种情况下会有sql注入吗?
$mastersInCity = DB::select('SELECT
master_user.master_id,
masters.specialization,
category_letter_master.category_letter_id AS master_letter,
COUNT(*) AS count_in_city
FROM master_user
LEFT JOIN masters ON master_user.master_id = masters.id
LEFT JOIN category_letter_master ON category_letter_master.master_id = master_user.master_id
WHERE ' . $chooiseId . ' = ' . $cityId . ' GROUP
BY master_user.master_id, master_letter');或者,在这种情况下,最好直接使用PDO,这样可以自己手动准备请求吗?
发布于 2018-12-11 14:57:19
$mastersInCity = DB::select('SELECT
master_user.master_id,
masters.specialization,
category_letter_master.category_letter_id AS master_letter,
COUNT(*) AS count_in_city
FROM master_user
LEFT JOIN masters ON master_user.master_id = masters.id
LEFT JOIN category_letter_master ON category_letter_master.master_id = master_user.master_id
WHERE ? = ? GROUP
BY master_user.master_id, master_letter', [$chooiseId, $cityId]);这相当于准备好的陈述。
博士:https://laravel.com/docs/5.7/database#running-queries
编辑:我相信只要有口才就能做到这一点,这里没有什么太复杂的。类似于:
MasterUser::with(['master', 'master_letter'])->withCount()->where($chooiseId, $cityId)->get()https://stackoverflow.com/questions/53726750
复制相似问题