我有一个应用程序,它应该允许用户从数据库中的表中查看宠物。
网页设计图片及Pets数据表:

下面是我的按钮代码:
protected void viewAnimalsBreedButton_Click(object sender, EventArgs e)
{
try
{
SqlConnection cnn = new SqlConnection("Data Source=(LocalDB)\\MSSQLLocalDB;AttachDbFilename=|DataDirectory|\\FrendsWithPaws.mdf;Integrated Security=True");
cnn.Open();
SqlCommand command = new SqlCommand("SELECT PetID, Breed, Name, Age, Gender, Picture, Sanctuary FROM Pets WHERE Breed='+ breedDropDownList.SelectedValue +'", cnn);
SqlDataReader reader = command.ExecuteReader();
petsGridView.DataSource = reader;
petsGridView.DataBind();
cnn.Close();
}
catch (Exception ex)
{
Response.Write("error" + ex.ToString());
}
}首先,我有一个宠物品种的dropdownlist,当我在dropdown中选择一个breed并单击查看动物时,我希望gridview向我展示这个品种的宠物(包含大部分信息).我希望这个能为Species和Sanctuary工作.
目前,当我选择一个品种并单击“查看动物”时,不会发生任何事情,如下图所示:
选择“家”品种后的网页形式图片,点击“查看动物”按钮:

我怎么才能让这个起作用?
发布于 2018-12-11 14:11:28
首先,您应该始终使用参数化查询来避免SQL注入,并获得这类问题的解决方案。其次,您需要创建一个DataTable并通过数据读取器填充它,并将表绑定到网格:
cnn.Open();
SqlCommand command = new SqlCommand("SELECT PetID, Breed, Name, Age, Gender, Picture, " +
"Sanctuary FROM Pets where Breed = @Breed ", cnn);
command.Parameters.AddWithValue("@Breed", breedDropDownList.SelectedValue);
DataTable table = new DataTable();
table.Load(command.ExecuteReader());
petsGridView.DataSource = table;
petsGridView.DataBind();
cnn.Close();尽管直接指定类型并使用Value属性,但它比AddWithValue更好。https://blogs.msmvps.com/jcoehoorn/blog/2014/05/12/can-we-stop-using-addwithvalue-already/
发布于 2018-12-11 14:13:27
您必须首先将读取的数据加载到datatable:
protected void viewAnimalsBreedButton_Click(object sender, EventArgs e)
{
try
{
SqlConnection cnn = new SqlConnection("Data Source=(LocalDB)\\MSSQLLocalDB;AttachDbFilename=|DataDirectory|\\FrendsWithPaws.mdf;Integrated Security=True");
cnn.Open();
SqlCommand command = new SqlCommand("SELECT PetID, Breed, Name, Age, Gender, Picture, Sanctuary FROM Pets WHERE Breed='" + breedDropDownList.SelectedValue + "'", cnn);
SqlDataReader reader = command.ExecuteReader();
var dataTable = new DataTable();
dataTable.Load(dataReader);
petsGridView.DataSource = dataTable;
petsGridView.DataBind();
cnn.Close();
}
catch (Exception ex)
{
Response.Write("error" + ex.ToString());
}
}https://stackoverflow.com/questions/53725895
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