QKeySequence在PySide和PySide2中的差异

Question

由于我目前正在将gui应用程序从Python2.7.14/PySide1.2.4移植到Python3.7.1/PySide25.11.2，所以我遇到了快捷机制方面的一些问题。更具体而言：

• QKeySequence实例化似乎在PySide2中返回与PySide不同的/令人惊讶的结果。
• +操作符在Qt.Key_*枚举上似乎没有返回预期的结果。例如，QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)似乎不能正常工作。
• 当使用字符串代码实例化QKeySequences时，它可以工作，例如，QKeySequence("Shift+Ctrl+Z")看起来很实用。
• 使用类似于QKeySequence.StandardKey的QKeySequence(QKeySequence.Redo)实例化简单地在PySide2中崩溃。

这些是已知的虫子吗？预期的使用有什么变化吗？我想念文档里的东西吗？

Win7x64/Python3.7.1/PySide25.11.2(失灵/崩溃)

# -*- coding: utf-8 -*-
"""Test QKeySequence equality/matching in PySide2."""
from PySide2.QtCore import Qt
from PySide2.QtGui import QKeySequence

sequence_a = QKeySequence("Shift+Ctrl+Z")
sequence_b = QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)

# string representation
print(sequence_a.toString())
print(sequence_b.toString())

print("-"*20)

# equality/matching
print(sequence_a.matches(sequence_b))
print(sequence_a == sequence_b)

print("-"*20)

# this causes a crash in PySide2 (Process finished with exit code -1073741819 (0xC0000005))
print(QKeySequence(QKeySequence.Redo))

# Ctrl+Shift+Z
# [
# --------------------
# PySide2.QtGui.QKeySequence.SequenceMatch.NoMatch
# False
# --------------------
# Process finished with exit code -1073741819 (0xC0000005)

Win7x64/Python2.7.14/PySide 1.2.4 (工作)

# -*- coding: utf-8 -*-
"""Test QKeySequence equality/matching in PySide."""
from PySide.QtCore import Qt
from PySide.QtGui import QKeySequence

sequence_a = QKeySequence("Shift+Ctrl+Z")
sequence_b = QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z)

# string representation
print(sequence_a.toString())
print(sequence_b.toString())

print("-"*20)

# equality/matching
print(sequence_a.matches(sequence_b))
print(sequence_a == sequence_b)

print("-"*20)

# this works in PySide
print(QKeySequence(QKeySequence.Redo))

# Ctrl+Shift+Z
# Ctrl+Shift+Z
# --------------------
# PySide.QtGui.QKeySequence.SequenceMatch.ExactMatch
# True
# --------------------
# PySide.QtGui.QKeySequence(67108953, 0, 0, 0)

Answer 1

就目前而言，出现了两个可能的解决办法：

• 错误： QKeySequence(Qt.SHIFT + Qt.CTRL + Qt.Key_Z).toString() -> "["
• 具有强制优先级的修补程序： QKeySequence(Qt.SHIFT + (Qt.CTRL + Qt.Key_Z)).toString() -> "Ctrl+Shift+Z"
• 按位或运算符的修正： QKeySequence(Qt.ShiftModifier | Qt.CTRL | Qt.Key_Z).toString() -> "Ctrl+Shift+Z"

虽然他们似乎解决了眼前的直接问题，但由于种种原因，我并不认为他们那么伟大。一般的问题可能仍然可以被称为PySide2 bug!？