如何将包含value，value的数组转换为只包含key，value的单个对象？

Question

因此，在为数据库绘制数据之后，我得到了类似这样的结果

[
{name: "id", data_type: "integer"}
{name: "name", data_type: "char"}
{name: "active", data_type: "boolean"}
]

但我想要的是：

{id: "integer" , name: "char" , active: "boolean" }

我试了一大堆东西，但都没弄明白，任何帮助都将不胜感激

这是我孤注一掷的尝试：

Object.entries(jsonData).map((type) => {
        return { ...objectList, [type[1].name]: type[1].data_type };
      }).reduce((objectList, object) => (
          ...objectList,
          object)
        )

Answer 1

下面是一个简单的方法：

​

let arr = [
{name: "id", data_type: "integer"},
{name: "name", data_type: "char"},
{name: "active", data_type: "boolean"}
];
let map = {};
arr.forEach(e => map[e.name]=e.data_type);
console.log(map);

​

如果你想使用.reduce，试试这个：

let arr = [
{name: "id", data_type: "integer"},
{name: "name", data_type: "char"},
{name: "active", data_type: "boolean"}
];
let map = arr.reduce(function(obj,item){
  obj[item.name] = item.data_type; 
  return obj;
}, {});
console.log(map);

​

Answer 2

这是一个缩减

​

const data = [
{name: "id", data_type: "integer"},
{name: "name", data_type: "char"},
{name: "active", data_type: "boolean"}
];

const arrayToObject = arr => arr.reduce((result, value) => {
  result[value.name] = value.data_type;
  return result;
}, {});

console.log(arrayToObject(data));

​

Answer 3

另一种方法是使用Array.reduce()

const array = [
  { name: 'id', data_type: 'integer' },
  { name: 'name', data_type: 'char' },
  { name: 'active', data_type: 'boolean' },
];

const newObject = array.reduce((finalObj, obj) => {
  finalObj[obj.name] = obj.data_type;
  return finalObj;
}, {})

console.log(newObject)