数据库层次结构如下
作为结构,预期产出是
学生姓名-费用->奖学金1,Scholarship2
Karan-1.Annual Fee->Economic Scholarship,Incapable Scholarship,2.Monthly Fee 但我得到的是
学生姓名-费用->奖学金1,学生姓名-费用->奖学金2
Karan-1.Annual Fee->Economic Scholarship,1.Annual Fee->Incapable Scholarship,2.Monthly Fee这里面怎么了?虽然我在嵌套CONCAT,但没有得到预期的输出
CONCAT(student.en_ttl,'-',GROUP_CONCAT(DISTINCT fee.id,'.',fee.en_ttl,
COALESCE(CONCAT('->',sch.en_ttl),''))) AS feeSQL Fiddle
发布于 2018-11-28 14:46:43
您基本上需要两个级别的GROUP BY。因此,我们需要在这里使用一个派生表。第一个子查询将在fee级别进行聚合;然后第二个级别将这些费用详细信息聚合到student级别。
此外,在更新的(和ANSI兼容的)版本的MySQL中,您需要确保SELECT子句中的任何非聚合列也应该在GROUP BY子句中。
查询
SELECT
CONCAT(stud_ttl,'-',GROUP_CONCAT(CONCAT(fee_det, COALESCE(CONCAT('->',fee_sch), '')))) AS fee
FROM
(
SELECT student.ttl AS stud_ttl,
CONCAT(fee.id,'.',fee.ttl) AS fee_det,
Group_concat(DISTINCT sch.ttl) AS fee_sch
FROM inv_id
JOIN student
ON student.id = inv_id.std
JOIN inv_lst
ON inv_lst.ftm = inv_id.ftm
JOIN fee
ON fee.id = inv_lst.fee
JOIN sec_fee
ON sec_fee.fee = fee.id
AND sec_fee.cls = student.cls
AND sec_fee.sec = student.sec
LEFT JOIN std_sch
ON std_sch.std = student.id
LEFT JOIN sec_sch
ON sec_sch.sch = std_sch.sch
AND sec_sch.fee = fee.id
LEFT JOIN sch
ON sch.id = sec_sch.sch
GROUP BY student.ttl, fee_det, fee.ttl
) dt
GROUP BY stud_ttl;结果
| fee |
| -------------------------------------------------------------------- |
| Karan-1.Annual->Economic Scholarship,Incapable Scholarship,2.Monthly |https://stackoverflow.com/questions/53522029
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