Python:在查找列表中最小数的最长序列长度时，输出不正确

Question

我试图在列表中找到最小数的最长序列。例如，对于这个列表，resp_rates = [1,1,2,89,56,4,1,1,1,1,10,5,67,1,1,1,76,5,7,6,6,6,1,1,1,1,1,1,1]，最小数为1，1的序列长度分别为，2，4，3，7。因此，最长序列的长度是7，但是，我的代码打印4。

代码：

resp_rates = [1,1,2,89,56,4,1,1,1,1,10,5,67,1,1,1,76,5,7,6,6,6,1,1,1,1,1,1,1]
rr_min_current = np.amin(resp_rates)
print(rr_min_current)
count = 0
first = 1
min_rr_sequence = []
print(resp_rates)
for resp_rate in resp_rates:
    if resp_rate == rr_min_current and first == 1:
        count=count+1 
        first = 0
    elif resp_rate == rr_min_current and first == 0:
        count=count+1
    elif resp_rate != rr_min_current and first == 0:    
        min_rr_sequence.append(count)
        first = 1
        count = 0
#longest_min_rr_sequence.append(np.amax(min_rr_sequence))
print(min_rr_sequence)
longest_min_rr_sequence = np.amax(min_rr_sequence)
print(longest_min_rr_sequence)

输出：

1
[1, 1, 2, 89, 56, 4, 1, 1, 1, 1, 10, 5, 67, 1, 1, 1, 76, 5, 7, 6, 6, 6, 1, 1, 1, 1, 1, 1, 1]
[2, 4, 3]
4

Answer 1

给您(编辑)：

resp_rates = [1,1,1,1,1,1,1,1,1,1,1,2,89,56,4,1,1,1,1,10,5,67,1,1,1,76,5,7,6,6,6,1,1,1,1,1,1,1]

lowest = resp_rates[0]
count = 0
max_count = 0

for i in resp_rates:
    if i < lowest:
        lowest = i
        count = 1
        max_count = count
    elif i == lowest:
        count = count + 1
        if count > max_count:
            max_count = count
    else:
        count = 0


print(max_count)

Answer 2

使用groupby的简短解决方案

from itertools import groupby

resp_rates = [1,1,2,89,56,4,1,1,1,1,10,5,67,1,1,1,76,5,7,6,6,6,1,1,1,1,1,1,1]

out = -min((value, -len(list(group))) for value, group in groupby(resp_rates))[1]
print(out)
# 7

一些解释：(value, -len(list(group))) for value, group in groupby(resp_rates))生成元组：(1, -2), (2, -1), (89, -1), ... (1, -4) ...

取min将返回具有最小值的元组，如果许多元组具有相同的最小值，则返回长度最大的元组(因此可以使用-length来实现最小值)。

我们只需要保持长度远离最小的元组，并改变它的符号。

Answer 3

这样做：

In [72]: resp_rates = [1,1,2,89,56,4,1,1,1,1,10,5,67,1,1,1,76,5,7,6,6,6,1,1,1,1,1,1,1]

In [73]: import itertools,operator
In [83]: r = max((list(y) for (x,y) in itertools.groupby((enumerate(resp_rates)),operator.itemgetter(1)) if x == min(resp_rates)), key=len)

In [84]: len(r)
Out[84]: 7