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Spring mongo审核@版本问题
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Stack Overflow用户
提问于 2018-11-10 18:19:31
回答 2查看 3.8K关注 0票数 3

我刚刚开始一个新的项目,我想使用SprintBoot2.1,并且在一开始就遇到了一个问题。我想做的是使用来管理数据库。我希望使用@Version注释实现一个乐观的锁定。但是,我发现@Version似乎会影响MongoRepository中的save()行为,这意味着dup键错误。

下面是示例代码。

POJO

代码语言:javascript
复制
    @Data
    @AllArgsConstructor
    @NoArgsConstructor
    @Document
    public class Person {

        @Id public ObjectId id;
        @CreatedDate public LocalDateTime createOn;
        @LastModifiedDate public LocalDateTime modifiedOn;
        @Version public long version;
        private String name;
        private String email;

        public Person(String name, String email) {
            this.name = name;
            this.email = email;
        }

       @Override
        public String toString() {
            return String.format("Person [id=%s, name=%s, email=%s, createdOn=%s, modifiedOn=%s, version=%s]", id, name, email, createOn, modifiedOn, version);
        }
    }

MongoConfig

代码语言:javascript
复制
    @Configuration
    @EnableMongoRepositories("com.project.server.repo")
    @EnableMongoAuditing
    public class MongoConfig {

    }

仓库

代码语言:javascript
复制
    public interface PersonRepo extends MongoRepository<Person, ObjectId> {
        Person save(Person person);
        Person findByName(String name);
        Person findByEmail(String email);
        long count();
        @Override
        void delete(Person person);
    }

正如官方医生中所指出的,我的version字段在long中,但是dup键错误发生在第二个save,这意味着它再次尝试insert,即使在对象中有id。

我也尝试过在Long字段中使用version,它没有发生dup键,并按预期的更新保存,但是createdOn变成了第一个save中的null (意思是insert)。

控制器

代码语言:javascript
复制
Person joe = new Person("Joe", "aa@aa.aa");
System.out.println(joe.toString());
this.personRepo.save(joe);
Person who = this.personRepo.findByName("Joe");
System.out.println(who.toString());
who.setEmail("bb@bb.bb");
this.personRepo.save(who);
Person who1 = this.personRepo.findByName("Joe");
Person who2 = this.personRepo.findByEmail("bb@bb.bb");
System.out.println(who1.toString());
System.out.println(who2.toString());

带有dup密钥的日志(long version)

代码语言:javascript
复制
    2018-11-11 02:09:31.435  INFO 4319 --- [on(6)-127.0.0.1] org.mongodb.driver.connection            : Opened connection [connectionId{localValue:2, serverValue:186}] to localhost:27017
    Person [id=null, name=Joe, email=aa@aa.aa, createdOn=null, modifiedOn=null, version=0]
    2018-11-11 02:09:37.254 DEBUG 4319 --- [nio-8080-exec-1] o.s.data.auditing.AuditingHandler        : Touched Person [id=null, name=Joe, email=aa@aa.aa, createdOn=2018-11-11T02:09:37.252, modifiedOn=2018-11-11T02:09:37.252, version=0] - Last modification at 2018-11-11T02:09:37.252 by unknown
    2018-11-11 02:09:37.259 DEBUG 4319 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : Inserting Document containing fields: [createOn, modifiedOn, version, name, email, _class] in collection: person
    2018-11-11 02:09:37.297 DEBUG 4319 --- [nio-8080-exec-1] o.s.d.m.r.query.MongoQueryCreator        : Created query Query: { "name" : "Joe" }, Fields: { }, Sort: { }
    2018-11-11 02:09:37.304 DEBUG 4319 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : find using query: { "name" : "Joe" } fields: Document{{}} for class: class com.seedu.server.model.Person in collection: person
    Person [id=5be71ee11ad34410df06852c, name=Joe, email=aa@aa.aa, createdOn=2018-11-11T02:09:37.252, modifiedOn=2018-11-11T02:09:37.252, version=0]
    2018-11-11 02:09:37.323 DEBUG 4319 --- [nio-8080-exec-1] o.s.data.auditing.AuditingHandler        : Touched Person [id=5be71ee11ad34410df06852c, name=Joe, email=bb@bb.bb, createdOn=2018-11-11T02:09:37.323, modifiedOn=2018-11-11T02:09:37.323, version=0] - Last modification at 2018-11-11T02:09:37.323 by unknown
    2018-11-11 02:09:37.324 DEBUG 4319 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : Inserting Document containing fields: [_id, createOn, modifiedOn, version, name, email, _class] in collection: person
    org.springframework.dao.DuplicateKeyException: E11000 duplicate key error collection: seedu.person index: _id_ dup key: { : ObjectId('5be71ee11ad34410df06852c') }; nested exception is com.mongodb.MongoWriteException: E11000 duplicate key error collection: seedu.person index: _id_ dup key: { : ObjectId('5be71ee11ad34410df06852c') }

日志与createdDate空 (Long version)

代码语言:javascript
复制
    2018-11-11 02:07:28.858  INFO 4310 --- [on(6)-127.0.0.1] org.mongodb.driver.connection            : Opened connection [connectionId{localValue:2, serverValue:183}] to localhost:27017
    Person [id=null, name=Joe, email=aa@aa.aa, createdOn=null, modifiedOn=null, version=null]
    2018-11-11 02:07:31.519 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.auditing.AuditingHandler        : Touched Person [id=null, name=Joe, email=aa@aa.aa, createdOn=null, modifiedOn=2018-11-11T02:07:31.518, version=0] - Last modification at 2018-11-11T02:07:31.518 by unknown
    2018-11-11 02:07:31.525 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : Inserting Document containing fields: [modifiedOn, version, name, email, _class] in collection: person
    2018-11-11 02:07:31.564 DEBUG 4310 --- [nio-8080-exec-1] o.s.d.m.r.query.MongoQueryCreator        : Created query Query: { "name" : "Joe" }, Fields: { }, Sort: { }
    2018-11-11 02:07:31.571 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : find using query: { "name" : "Joe" } fields: Document{{}} for class: class com.seedu.server.model.Person in collection: person
    Person [id=5be71e631ad34410d6a3b123, name=Joe, email=aa@aa.aa, createdOn=null, modifiedOn=2018-11-11T02:07:31.518, version=0]
    2018-11-11 02:07:31.590 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.auditing.AuditingHandler        : Touched Person [id=5be71e631ad34410d6a3b123, name=Joe, email=bb@bb.bb, createdOn=null, modifiedOn=2018-11-11T02:07:31.590, version=1] - Last modification at 2018-11-11T02:07:31.590 by unknown
    2018-11-11 02:07:31.598 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : Calling update using query: { "_id" : { "$oid" : "5be71e631ad34410d6a3b123" }, "version" : { "$numberLong" : "0" } } and update: { "modifiedOn" : { "$date" : 1541873251590 }, "version" : { "$numberLong" : "1" }, "name" : "Joe", "email" : "bb@bb.bb", "_class" : "com.seedu.server.model.Person" } in collection: person
    2018-11-11 02:07:31.602 DEBUG 4310 --- [nio-8080-exec-1] o.s.d.m.r.query.MongoQueryCreator        : Created query Query: { "name" : "Joe" }, Fields: { }, Sort: { }
    2018-11-11 02:07:31.602 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : find using query: { "name" : "Joe" } fields: Document{{}} for class: class com.seedu.server.model.Person in collection: person
    2018-11-11 02:07:31.603 DEBUG 4310 --- [nio-8080-exec-1] o.s.d.m.r.query.MongoQueryCreator        : Created query Query: { "email" : "bb@bb.bb" }, Fields: { }, Sort: { }
    2018-11-11 02:07:31.604 DEBUG 4310 --- [nio-8080-exec-1] o.s.data.mongodb.core.MongoTemplate      : find using query: { "email" : "bb@bb.bb" } fields: Document{{}} for class: class com.seedu.server.model.Person in collection: person
    Person [id=5be71e631ad34410d6a3b123, name=Joe, email=bb@bb.bb, createdOn=null, modifiedOn=2018-11-11T02:07:31.590, version=1]
    Person [id=5be71e631ad34410d6a3b123, name=Joe, email=bb@bb.bb, createdOn=null, modifiedOn=2018-11-11T02:07:31.590, version=1]

如我所知,spring使用id存在作为保存行为控件,这意味着如果id存在,则保存将类似于mongo的insert。然而,在这里,版本似乎也影响保存行为或影响spring识别id存在的方式。

问:如何将MongoAudit与MongoRepository结合使用?我犯了什么错误/错误吗?

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回答 2

Stack Overflow用户

回答已采纳

发布于 2019-01-11 15:39:53

我还是找不出问题。然而,尽管我的设置与上面的post完全相同,但由于我将Spring从2.1.0升级到2.1.1,现在一切正常(不管我使用的是哪种版本,Long/long)

下面是我现在使用的库版本。

代码语言:javascript
复制
spring-boot-starter-data-mongodb:2.1.1.RELEASE:
  -> spring-data-mongo:2.1.3.RELEASE
  -> mongodb-driver:3.8.2
票数 1
EN

Stack Overflow用户

发布于 2019-10-30 14:23:02

为了使用@Version,您必须首先从数据库中检索数据模型,在更新数据之后,您必须将相同的数据保存到数据库中。例如:

代码语言:javascript
复制
  personRepo.findByName(name).ifPresent(person-> {
            person.setEmail("email@gamil.com");
            personRepo.save(person);
            log.info("Updated Data: {}", person);
        });

如果没有将@CreatedDate添加到模型类中,那么null将始终是@Version。它适用于@Version

如果您没有将@Version添加到您的模型类中,并且试图通过使用模型类@Version进行相同的更新,那么这里还需要添加一点,这将再次给出重复的id错误。

票数 3
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/53242033

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