使用C的Arduino不接收Python输入

Question

因此，我有一个学校项目，我们必须向Arduino Uno发送命令，当它接收到命令时，它将从传感器返回数据。现在，我让它工作到一个部分，如果我发送一个命令对putty，它会对它作出反应。但问题是:当我通过Python发送命令时，它不会对它做任何事情。为了清楚起见，我可以用Python接收我的传感器的输出，但是我有一个C程序不断地推动我的数据。

下面是我的Python代码：

import serial,time
ComPort = serial.Serial('COM3')
ComPort.baudrate = 19200
ComPort.bytesize = 8
ComPort.parity = 'N'
ComPort.stopbits = 1
data = "4"
data = data.encode("utf-8")
time.sleep(1.6)
ComPort.write(data)
out = " "
i = 0
while i < 1:
   while ComPort.inWaiting() > 0: 
      out +=ComPort.read(1).decode()
      i = i + 1
ComPort.close()

这是我的C代码；我遗漏了一些部分，因为这与传感器有关，传感器工作正常。

#define F_CPU 16E6
#include <avr/interrupt.h>
#include <util/delay.h>
#include <stdlib.h>

#define UBBRVAL 51
void uart_init() {
    // set the baud rate
    UBRR0H = 19200;
    UBRR0L = UBBRVAL;
    // disable U2X mode
    UCSR0A = 0;
    // enable transmitter and receiver
    UCSR0B = _BV(TXEN0)|_BV(RXEN0);
    // set frame format : asynchronous, 8 data bits, 1 stop bit, no parity
    UCSR0C = _BV(UCSZ01) | _BV(UCSZ00);
}

void UART_Putstring(char* eenstring)
{
    while(*eenstring != 0X00)
    {
        transmit(*eenstring);
        eenstring++;
    }
}

unsigned char receive( void )
{
    /* Wait for data to be received */
    while ( !(UCSR0A & (1<<RXC0)) );
    /* Get and return received data from buffer */
    return UDR0;
}
void transmit(uint8_t data)
{
    // wait for an empty transmit buffer
    // UDRE is set when transmit buffer is empty
    loop_until_bit_is_set(UCSR0A, UDRE0);
    // send the data
    UDR0 = data;
}

int main(void)
{
    char tot_string[6];
    uint8_t tijdelijk;
    float tijdelijk_float;
    char input;

    DDRD |= 1<<5; // Setup HC-SR04 Trigger as an output
    DDRD &= ~(1<<4); // Setup HC-SR04 Echo a an input
    _delay_ms(50);
    uart_init();

    while(1)
    {   
        input = receive();
        if(input==0x34)
        {
            // This is converting sensor Data
            tijdelijk = hcsr04();
            tijdelijk_float = (float)(tijdelijk) * 40;
            tijdelijk_float = tijdelijk_float/58; 
            dtostrf(tijdelijk_float, 2, 2, tot_string);
            UART_Putstring(tot_string);
        }               
    }
} 

Answer 1

所以我找到了答案，真的很简单。只需在C中这样做：

if(input() == '4')
{
    tijdelijk = hcsr04();
    tijdelijk_float = (float)(tijdelijk) * 40;
    tijdelijk_float = tijdelijk_float/58; 
    dtostrf(tijdelijk_float, 2, 2, tot_string);
    UART_Putstring(tot_string);
}