我想在感兴趣的区域内探测到线。我的输出图像应该在选定的ROI中显示原始图像和检测到的行。到目前为止,在原始图像中查找线条或选择ROI并不是一个问题,但仅在ROI中查找线条不起作用。我的MWE读取图像,将其转换为灰度,并允许我选择ROI,但当HoughLinesP想读取roi时会出现错误。
import cv2
import numpy as np
img = cv2.imread('example.jpg',1)
gray = cv2.cvtColor(img ,cv2.COLOR_BGR2GRAY)
# Select ROI
fromCenter = False
roi = cv2.selectROI(gray, fromCenter)
# Crop ROI
roi = img[int(roi[1]):int(roi[1]+roi[3]), int(roi[0]):int(roi[0]+roi[2])]
# Find lines
minLineLength = 100
maxLineGap = 30
lines = cv2.HoughLinesP(roi,1,np.pi/180,100,minLineLength,maxLineGap)
for x in range(0, len(lines)):
for x1,y1,x2,y2 in lines[x]:
cv2.line(img,(x1,y1),(x2,y2),(237,149,100),2)
cv2.imshow('Image',img)
cv2.waitKey(0) & 0xFF
cv2.destroyAllWindows()控制台显示:
lines = cv2.HoughLinesP(roi,1,np.pi/180,100,minLineLength,maxLineGap) C:\Miniconda3\conda-bld\opencv-suite_1533128839831\work\modules\imgproc\src\hough.cpp:441:错误:(-215) image.type() == (0)和(1 << 3) - 1)) +(1)-1) << 3)
我的假设是roi没有正确的格式。我使用Python3.6和Spyder3.2.8。谢谢你的帮助!
发布于 2018-11-08 01:42:47
函数cv2.HoughLinesP需要一个单通道图像,因此可以从灰度图像中提取裁剪区域,这将消除错误:
# Crop the image
roi = list(map(int, roi)) # Convert to int for simplicity
cropped = gray[roi[1]:roi[1]+roi[3], roi[0]:roi[0]+roi[2]]请注意,我将输出名从roi更改为cropped,这是因为您仍然需要roi框。点x1、x2、y1和y2是裁剪图像中的像素位置,而不是完整图像。要正确绘制图像,只需从roi添加左上角像素位置即可。下面是具有相关编辑的for循环:
# Find lines
minLineLength = 100
maxLineGap = 30
lines = cv2.HoughLinesP(cropped,1,np.pi/180,100,minLineLength,maxLineGap)
for x in range(0, len(lines)):
for x1,y1,x2,y2 in lines[x]:
cv2.line(img,(x1+roi[0],y1+roi[1]),(x2+roi[0],y2+roi[1]),(237,149,100),2)https://stackoverflow.com/questions/53190155
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