我面临的问题是打印所有文件属于一个特定的子文件夹在windows。
概述:
我有一个windows VM,其IP地址为10.162.12.12
我想打印C:\MyFolder\MySubFolder下面的所有文件名
目前“MySubFolder”包含4个cmd文件,即a.cmd、b.cmd、c.cmd、d.cmd
try (Connection connection = client.connect("10.162.x.x")) {
AuthenticationContext ac = new AuthenticationContext("userName", "pwd".toCharArray(), "domainName");
Session session = connection.authenticate(ac);
// Connect to Share
try (DiskShare share = (DiskShare) session.connectShare("MyFolder")) {
for (FileIdBothDirectoryInformation f : share.list("/MySubFolder")) {
System.out.println("File : " + f.getFileName());
}
} catch (Exception e) {
e.printStackTrace();
}我不知道如何传递我的"C“驱动器信息和路径,即在哪里传递path.Currently,我得到以下错误:
15:48:17.991 INFO c.h.smbj.connection.Connection -成功连接到: 10.162.12.12 15:48:18.826 INFO c.h.smbj.connection.Connection -在10.162.12.12成功地验证了userName,会话是140737488355349 15:48:18.826 INFO com.hierynomus.smbj.session.Session -在会话140737488355349上连接到\ 10.162.12.12 \MyFolder 15:48:19.357 INFO com.hierynomus.smbj.session.Session -从主机10.162.12.12注销会话140737488355349.hierynomus.smbj.session.Session.connectShare(Session.java:144) at com.olf.agon.smbj.SMBFile3Trail.main(SMBFile3Trail.java:36)
我只想知道如何将该值传递给我的connectionShare()方法和list()方法,以便能够连接到"\10.162.12.12\C\MyFolder“。
发布于 2018-11-02 13:02:45
我解决了这个问题:
SmbConfig smbConfig = SmbConfig
.builder()
.withMultiProtocolNegotiate(true)
.withTransportLayerFactory(new AsyncDirectTcpTransportFactory<>())
.withSigningRequired(true).build();
final String SHARE_NAME = "C$";
final String LOCAL_PATH = "MyFolder/MySubFolder";
SMBClient client = new SMBClient(smbConfig);
try (Connection connection = client.connect("10.162.12.12")) {
AuthenticationContext ac = new AuthenticationContext("userName", "pwd".toCharArray(), "domainName");
Session session = connection.authenticate(ac);
// Connect to Share
try (DiskShare share = (DiskShare) session.connectShare(SHARE_NAME)) {
for (FileIdBothDirectoryInformation f : share.list(LOCAL_PATH)) {
System.out.println("File : " + f.getFileName());
}
} catch (Exception e) {
e.printStackTrace();
}
} catch (Exception e) {
e.printStackTrace();
} finally {
client.close();
}https://stackoverflow.com/questions/53117162
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