使用Stack Exchange数据资源管理器(SEDE)按帖子数量和信誉查找用户

Question

我想找出哪些用户在帖子数量最少(少于10篇)中享有最大的声誉。但是为什么在加入之前我不能有一个where子句呢？：

SELECT TOP 100 Users.Id, Users.DisplayName AS [Username], Users.Reputation, COUNT(Posts.Id) AS [Post Count] FROM Users
//WHERE COUNT(Posts.Id) < 10
JOIN Posts ON Posts.OwnerUserId = Users.Id 
GROUP BY Users.Id, Users.DisplayName, Users.Reputation
ORDER BY Users.Reputation DESC;

原始用户post计数示例查询位于data.stackexchange.com/stackoverflow/query/503051

Answer 1

这就是子句 (MS参考)的目的。

你可以使用：

SELECT TOP 100 Users.Id, Users.DisplayName AS [Username], Users.Reputation, COUNT(Posts.Id) AS [Post Count] FROM Users
JOIN Posts ON Posts.OwnerUserId = Users.Id
GROUP BY Users.Id, Users.DisplayName, Users.Reputation
HAVING COUNT(Posts.Id) < 10
ORDER BY Users.Reputation DESC;

但这就是，利用一些SEDE特征

-- maxRows: How many rows to return:
-- maxPosts: Maximum number of posts a user can have:

SELECT TOP ##maxRows:INT?100##
            'site://u/' + CAST(u.Id AS NVARCHAR) + '|' + u.DisplayName  AS [User]
            , u.Reputation
            , COUNT (p.Id)  AS [Post Count]
FROM        Users u
LEFT JOIN   Posts p         ON (p.OwnerUserId = u.Id  AND  p.PostTypeId IN (1, 2) )  -- Q & A only
GROUP BY    u.Id
            , u.DisplayName
            , u.Reputation
HAVING      COUNT (p.Id) <= ##maxPosts:INT?10##
ORDER BY    u.Reputation DESC
            , [Post Count]
            , u.DisplayName

你可以看它住在塞德。

我特别喜欢没有帖子的高代表用户。