更改Plutus.py比特币钱包地址范围

Question

我正在使用来自https://github.com/Isaacdelly/Plutus/blob/master/plutus.py的以下脚本

该脚本适用于2^160范围内的钱包地址。我很好奇，在脚本中，我可以将其更改为2^128范围或2^n范围。有没有可能有窗户呢？像2^0 - 2^100？

不试图做任何恶意的事情，只是试图获取数据，以表明即使选择范围也是徒劳的，因为有大量的地址。

 # Plutus Bitcoin Brute Forcer
# Made by Isaac Delly
# https://github.com/Isaacdelly/Plutus

try:
    import sys
    import os
    import time
    import hashlib
    import binascii
    import multiprocessing
    from multiprocessing import Process, Queue
    from multiprocessing.pool import ThreadPool
    import threading
    import base58
    import ecdsa
    import requests
except ImportError:
    import subprocess
    subprocess.check_call(["python", '-m', 'pip', 'install', 'base58==1.0.0'])
    subprocess.check_call(["python", '-m', 'pip', 'install', 'ecdsa==0.13'])
    subprocess.check_call(["python", '-m', 'pip', 'install', 'requests==2.19.1'])
    import base58
    import ecdsa
    import requests

def generate_private_key():
    return binascii.hexlify(os.urandom(32)).decode('utf-8')

def private_key_to_WIF(private_key):
    var80 = "80" + str(private_key) 
    var = hashlib.sha256(binascii.unhexlify(hashlib.sha256(binascii.unhexlify(var80)).hexdigest())).hexdigest()
    return str(base58.b58encode(binascii.unhexlify(str(var80) + str(var[0:8]))), 'utf-8')

def private_key_to_public_key(private_key):
    sign = ecdsa.SigningKey.from_string(binascii.unhexlify(private_key), curve = ecdsa.SECP256k1)
    return ('04' + binascii.hexlify(sign.verifying_key.to_string()).decode('utf-8'))

def public_key_to_address(public_key):
    alphabet = "123456789ABCDEFGHJKLMNPQRSTUVWXYZabcdefghijkmnopqrstuvwxyz"
    count = 0; val = 0
    var = hashlib.new('ripemd160')
    var.update(hashlib.sha256(binascii.unhexlify(public_key.encode())).digest())
    doublehash = hashlib.sha256(hashlib.sha256(binascii.unhexlify(('00' + var.hexdigest()).encode())).digest()).hexdigest()
    address = '00' + var.hexdigest() + doublehash[0:8]
    for char in address:
        if (char != '0'):
            break
        count += 1
    count = count // 2
    n = int(address, 16)
    output = []
    while (n > 0):
        n, remainder = divmod (n, 58)
        output.append(alphabet[remainder])
    while (val < count):
        output.append(alphabet[0])
        val += 1
    return ''.join(output[::-1])

def get_balance(address):
    try:
        response = requests.get("https://bitaps.com/api/address/" + str(address))
        return int(response.json()['balance']) 
    except:
        return -1

def data_export(queue):
    while True:
        private_key = generate_private_key()
        public_key = private_key_to_public_key(private_key)
        address = public_key_to_address(public_key)
        data = (private_key, address)
        queue.put(data, block = False)

def worker(queue):
    while True:
        if not queue.empty():
            data = queue.get(block = True)
            balance = get_balance(data[1])
            process(data, balance)

def process(data, balance):
    private_key = data[0]
    address = data[1]
    if (balance == 0):
        print("{:<34}".format(str(address)) + ": " + str(balance))
    if (balance > 0):
        file = open("plutus.txt","a")
        file.write("address: " + str(address) + "\n" +
                   "private key: " + str(private_key) + "\n" +
                   "WIF private key: " + str(private_key_to_WIF(private_key)) + "\n" +
                   "public key: " + str(private_key_to_public_key(private_key)).upper() + "\n" +
                   "balance: " + str(balance) + "\n\n")
        file.close()

def thread(iterator):
    processes = []
    data = Queue()
    data_factory = Process(target = data_export, args = (data,))
    data_factory.daemon = True
    processes.append(data_factory)
    data_factory.start()
    work = Process(target = worker, args = (data,))
    work.daemon = True
    processes.append(work)
    work.start()
    data_factory.join()

if __name__ == '__main__':
    try:
        pool = ThreadPool(processes = multiprocessing.cpu_count()*2)
        pool.map(thread, range(0, 10))
    except:
        pool.close()
        exit()

谢谢

Answer 1

你似乎误解了2^160位范围的目的。

每个标准的比特币地址都绑定到公钥的HASH160上。一个HASH160是160位长，这就是为什么你的搜索空间是2^160。如果您能够找到公钥的HASH160相等的两个私钥，那么这两个私钥中的任何一个都可以使用发送到该地址的硬币。

搜索更小的空间是没有意义的，因为您不再搜索比特币地址。如果您只想搜索随机散列函数，那么只需将RIPEMD160散列函数替换为另一个具有任意位大小的输出的散列函数。

请注意，如果您这样做，其余的代码谈论检查余额等将是无用的，因为您的输出将不再是一个比特币地址。