调试apk没有问题，但是在发布版apk中发现了GoogleSignInApi中的"signInResult:failed code=12500“异常

Question

package com.oct2018.hiding_this;
import android.content.Intent;
import android.support.annotation.NonNull;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Toast;
import com.google.android.gms.auth.api.signin.GoogleSignIn;
import com.google.android.gms.auth.api.signin.GoogleSignInAccount;
import com.google.android.gms.auth.api.signin.GoogleSignInClient;
import com.google.android.gms.auth.api.signin.GoogleSignInOptions;
import com.google.android.gms.common.api.ApiException;
import com.google.android.gms.tasks.OnCompleteListener;
import com.google.android.gms.tasks.Task;
import com.google.firebase.auth.AuthResult;
import com.google.firebase.auth.FirebaseAuth;
import com.google.firebase.auth.FirebaseUser;
public class MainActivity extends AppCompatActivity
{
 private FirebaseAuth mAuth;
  private static final int RC_SIGN_IN = 9001;
    public String TAG="GOsign";
    private GoogleSignInClient mGoogleSignInClient;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
                .requestEmail()
                .build();
        mGoogleSignInClient = GoogleSignIn.getClient(this, gso);
    }
    @Override
    public void onStart() {
        super.onStart();
        GoogleSignInAccount account = GoogleSignIn.getLastSignedInAccount(this);
        Toast.makeText(this, "OnStart", Toast.LENGTH_SHORT).show();
    }
    @Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);GoogleSignInClient.getSignInIntent(...);
        if (requestCode == RC_SIGN_IN) {
            Log.d(TAG,"RC_SIGN_IN");
            // The Task returned from this call is always completed, no need to attach
            // a listener.
            Task<GoogleSignInAccount> task = GoogleSignIn.getSignedInAccountFromIntent(data);
            handleSignInResult(task);
        }
    }
    // [END onActivityResult]
    // [START handleSignInResult]
    private void handleSignInResult(Task<GoogleSignInAccount> completedTask) {
        try {
            GoogleSignInAccount account = completedTask.getResult(ApiException.class);
            // Signed in successfully, show authenticated UI.
            Toast.makeText(this, "SignIn Successfullly", Toast.LENGTH_SHORT).show();
            Log.d(TAG,"Signedin Successfully");
        } catch (ApiException e) {
            // The ApiException status code indicates the detailed failure reason.
            // Please refer to the GoogleSignInStatusCodes class reference for more information.
            Log.w(TAG, "signInResult:failed code=" + e.getStatusCode())
        }
    }
    // [END handleSignInResult]
    // [START signIn]
    private void signIn() {
        Intent signInIntent = mGoogleSignInClient.getSignInIntent();
        startActivityForResult(signInIntent, RC_SIGN_IN);
    }
    // [END signIn]
    // [START signOut]
    private void signOut() {
        mGoogleSignInClient.signOut()
                .addOnCompleteListener(this, new OnCompleteListener<Void>() {
                    @Override
                    public void onComplete(@NonNull Task<Void> task) {
                        // [START_EXCLUDE]
                        Toast.makeText(MainActivity.this, "SignedOut", Toast.LENGTH_SHORT).show();
                        // [END_EXCLUDE]
                    }
                });
    }
    // [END signOut]
    // [START revokeAccess]
    private void revokeAccess() {
        mGoogleSignInClient.revokeAccess()
                .addOnCompleteListener(this, new OnCompleteListener<Void>() {
                    @Override
                    public void onComplete(@NonNull Task<Void> task) {
                        // [START_EXCLUDE]
                        //updateUI(null);
                        // [END_EXCLUDE]
                    }
                });
    }
    int i=0;
    public void login(View view)
    {
        if(i%2==0)
        signIn();
        else
            signOut();
        i++;
    }
}

signInResult:失败的code=12500

当我试图登录我的google帐户时，总是会发现。(在APK发布版中)

Answer 1

将您的Google服务更新为最新版本。在您正在测试的设备中，如果没有更新，请检查google服务版本，然后更新，然后再试一次。

您还需要在开发人员控制台中使用版本沙-1键进行配置。