我需要两个PyQt窗口在一台多显示器上同时运行:一个屏幕用于显示,另一个用于输入。在下面的示例中,我尝试使用带有按钮的简单窗口和带有标签的另一个窗口。当我按下按钮时,其他的windows标签文本应该会改变:
import sys
from PyQt5.QtCore import pyqtSlot
from PyQt5.QtWidgets import QApplication, QWidget, QDialog, QInputDialog,QDesktopWidget,QVBoxLayout,QPushButton,QMainWindow,QAction,QFileDialog,QGroupBox,QGridLayout,QLabel
class Control_Pannel(QWidget):
def __init__(self):
super().__init__()
self.title = 'Main Control Pannel'
self.left = 10
self.top = 10
self.width = 640
self.height = 400
self.text = "Display text"
self.InitializeUI()
def InitializeUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.left,self.top,self.width,self.height)
self.inputBox = QGroupBox("Display")
layout = QGridLayout()
layout.setColumnStretch(1, 4)
layout.setColumnStretch(2, 4)
button = QPushButton('Push here to change text')
layout.addWidget(button,0,0)
button.clicked.connect(self.on_click)
self.inputBox.setLayout(layout)
windowLayout = QVBoxLayout()
windowLayout.addWidget(self.inputBox)
self.setLayout(windowLayout)
self.show()
app = QApplication(sys.argv)
ex=InputWindows()
sys.exit(app.exec_())
@pyqtSlot()
def on_click(self):
InputWindows.text = "Modified text after button push"
print(InputWindows.text)
InputWindows.update()
##???? here i don't know how to make the changes be reflected in the other window, even if when i print the .text attribute it seems to have changed.
class InputWindows(QDialog):
def __init__(self):
super().__init__()
self.title = 'Display Pannel'
self.left = 5
self.top = 5
self.width = 300
self.height = 300
self.text = "Original Text"
self.InitializeUI()
def InitializeUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.left,self.top,self.width,self.height)
self.createDisplayGridLayout()
windowLayout = QVBoxLayout()
windowLayout.addWidget(self.horizontalGroupBox)
self.setLayout(windowLayout)
self.show()
def createDisplayGridLayout(self):
self.horizontalGroupBox = QGroupBox("Grid")
layout = QGridLayout()
layout.setColumnStretch(1, 4)
layout.setColumnStretch(2, 4)
self.label = QLabel(self.text)
layout.addWidget(self.label,0,0)
if __name__=='__main__':
app=QApplication(sys.argv)
ex=Control_Pannel()
sys.exit(app.exec_())有了InputWindows.update(),我得到了first argument of unbound method must have a type QWidget,如果我尝试InputWindows.label.update(),我就得到了type object inputwindows has no attribute label
发布于 2018-10-19 12:07:00
InputWindows是一个类,它是一个抽象,所以您通常需要创建一个对象,我问您:如果您有n个InputWindows,那么您将更新文本到哪个窗口呢?我们不知道,所以简单的逻辑表明,这样做是错误的。另一方面,将每个类看作一个黑匣子,在其中输入刺激并获得输出,在您的示例中,Control_Pannel必须有一个输出:新文本,但是输出是异步的,因为它是变化的,必须在更改时使用,而Qt中的输出是信号,所以我们必须创建它。另一方面,InputWindows必须接收信息才能创建更新QLabel中文本的插槽,如下所示:
import sys
from PyQt5 import QtCore, QtWidgets
class Control_Pannel(QtWidgets.QWidget):
sendSignal = QtCore.pyqtSignal(str)
def __init__(self):
super().__init__()
self.title = 'Main Control Pannel'
self.left = 10
self.top = 10
self.width = 640
self.height = 400
self.text = "Display text"
self.InitializeUI()
def InitializeUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.left,self.top,self.width,self.height)
self.inputBox = QtWidgets.QGroupBox("Display")
layout = QtWidgets.QGridLayout()
layout.setColumnStretch(1, 4)
layout.setColumnStretch(2, 4)
button = QtWidgets.QPushButton('Push here to change text')
layout.addWidget(button,0,0)
button.clicked.connect(self.on_click)
self.inputBox.setLayout(layout)
windowLayout = QtWidgets.QVBoxLayout(self)
windowLayout.addWidget(self.inputBox)
@QtCore.pyqtSlot()
def on_click(self):
text = "Modified text after button push"
self.sendSignal.emit(text)
class InputWindows(QtWidgets.QDialog):
def __init__(self):
super().__init__()
self.title = 'Display Pannel'
self.left = 5
self.top = 5
self.width = 300
self.height = 300
self.InitializeUI()
self.setText("Original Text")
@QtCore.pyqtSlot(str)
def setText(self, text):
self.label.setText(text)
def InitializeUI(self):
self.setWindowTitle(self.title)
self.setGeometry(self.left,self.top,self.width,self.height)
self.createDisplayGridLayout()
windowLayout = QtWidgets.QVBoxLayout(self)
windowLayout.addWidget(self.horizontalGroupBox)
self.setLayout(windowLayout)
def createDisplayGridLayout(self):
self.horizontalGroupBox = QtWidgets.QGroupBox("Grid")
layout = QtWidgets.QGridLayout()
layout.setColumnStretch(1, 4)
layout.setColumnStretch(2, 4)
self.label = QtWidgets.QLabel()
layout.addWidget(self.label, 0, 0)
self.horizontalGroupBox.setLayout(layout)
if __name__=='__main__':
app = QtWidgets.QApplication(sys.argv)
ex1 = Control_Pannel()
ex1.show()
ex2 = InputWindows()
ex2.show()
ex1.sendSignal.connect(ex2.setText)
sys.exit(app.exec_())https://stackoverflow.com/questions/52891742
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