在java中滚动两个骰子直到dice1大于dice2两次

Question

这些数据的输出是随机的，我为此创建了一个函数。我想要记录多少次的“尝试”它得到骰子一个比骰子连续两次两次。因此，当它连续两次变大时，我希望它打印出来(“d1比d2连续两次大”，“需要”+试用+“)。到目前为止，我有这个，但被卡住了：

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

              int d1 = Dice();
              int d2 = Dice();
              int trials = 0;

              for (int i = 0; i < 100000; i++) {
               if (t1 > t2) {
               trials++;
               if (t1 > t2) {
                trials++ 
               }
              }
             }

            System.out.println(trials);
    } 
} 

Answer 1

欢迎来到这里！这应该能行。看看你做错了几件事的评论和一些解释。

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {

  // initialize variables to be updated in the loop
  int trials = 0;
  Boolean lastTimeD1WasGreater = false;

  for (int i = 0; i < 100000; i++) {
    // always increment the counter!
    trials++;

    // you had the wrong variable names here.
    // also they must be INSIDE the loop or else they would always come out the same
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      if (lastTimeD1WasGreater) {
        // if it was greater both last time and this time then we're done!
        System.out.println("it took " + trials + " trials.");
        break;
      } else {
        // otherwise set this variable so we can be on the lookout next time.
        lastTimeD1WasGreater = true;
      }
    } else {
      // d1 was not greater, so we'll start looking for a pair in the next loop.
      lastTimeD1WasGreater = false;
    }
  }
}

Answer 2

这样做(将以下内容视为伪代码)：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            trials++;
        }
    }
    System.out.println(trials);
}

编辑：

要获得dice1值比dice2值连续两次大的尝试，可以执行以下操作：

public static int[] Dice() {
    int[] diceThrownTwoTimes = new int[2];
    diceThrownTwoTimes[0] = (int)(Math.random() * 6.0) + 1;
    diceThrownTwoTimes[1] = (int)(Math.random() * 6.0) + 1;
    return diceThrownTwoTimes;
} 

public static void main(String[] args) {
    int trials = 0;

    for (int i = 0; i < 100000; i++) {
        int[] d1 = Dice();
        int[] d2 = Dice();
        if (d1[0] > d2[0] && d1[1] > d2[1]) {
            break;
        }else{
            trials++;
        }
    }
    System.out.println(trials);
}

Answer 3

我会和

public static int Dice() {
  return (int)(Math.random() * 6.0) + 1;
}

public static void main(String[] args) {
  int trials = 0;
  int count = 0;

  while (count < 2) {
    int d1 = Dice();
    int d2 = Dice();

    if (d1 > d2) {
      ++count;
    } else {
      count = 0;
    }

    ++trials;
  }

  println("It took " + trials + " trials for d1 to be larger than d2 " + count + " times in a row.")
}