Security j_spring_security_check - HTTP 403
Security j_spring_security_check - HTTP 403
提问于 2018-10-03 21:42:44
我是春季保安公司的新成员。如果我按下登录，站点：check将与
HTTP Status 403 – Forbidden
Type Status Report
Message Forbidden
Description The server understood the request but refuses to authorize it.
Apache Tomcat/9.0.12这里是web.xml
<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/spring/webcontext/security-context.xml
</param-value>
</context-param>
<listener>
<listener-class>
org.springframework.web.context.ContextLoaderListener
</listener-class>
</listener>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<servlet>
<servlet-name>DefaultServlet</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<init-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/spring/webcontext/DispatcherServlet-context.xml</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>DefaultServlet</servlet-name>
<url-pattern>/</url-pattern>
</servlet-mapping>
</web-app>
login.jsp 在这里：<form action="<c:url value="/j_spring_security_check"></c:url>" method="post"> - /j_spring_security_check在红色上标记错误：Cannot resolve controller URL '/j_spring_security_check'
<%@page pageEncoding="UTF-8" contentType="text/html; charset=UTF-8" %>
<%@ taglib prefix="c" uri="http://java.sun.com/jsp/jstl/core" %>
<%@ taglib prefix="form" uri="http://www.springframework.org/tags/form" %>
<%@ taglib prefix="spring" uri="http://www.springframework.org/tags" %>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<link rel="stylesheet" href="//netdna.bootstrapcdn.com/bootstrap/3.0.0/css/bootstrap.min.css">
<title>Produkty</title>
</head>
<body>
<section>
<div class="jumbotron">
<div class="container">
<h1>Produkty</h1>
<p>Dodaj produkty</p>
</div>
</div>
</section>
<div class="container">
<div class="row">
<div class="col-md-4 col-md-offset-4">
<div class="panel panel-default">
<div class="panel-heading">
<h3 class="panel-title">Zaloguj się</h3>
</div>
<div class="panel-body">
<c:if test="${not empty error}">
<div class="alert alert-danger">
<spring:message code="AbstractUserDetailsAuthenticationProvider.badCredentials"/><br/>
</div>
</c:if>
<form action="<c:url value="/j_spring_security_check"></c:url>" method="post">
<fieldset>
<div class="form-group">
<input class="form-control" placeholder="Nazwa użytkownika" name='j_username' type="text">
</div>
<div class="form-group">
<input class="form-control" placeholder="Hasło" name='j_password' type="password" value="">
</div>
<input class="btn btn-lg btn-success btn-block" type="submit" value="Zaloguj się">
</fieldset>
</form>
</div>
</div>
</div>
</div>
</div>
</body>
</html>security-context.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:security="http://www.springframework.org/schema/security"
xsi:schemaLocation="http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-4.2.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/mvc/spring-mvc-4.3.xsd">
<security:http auto-config="true">
<security:intercept-url pattern="/products/add" access="hasRole('ROLE_ADMIN')"/>
<security:form-login login-page="/login" default-target-url="/products/add"
authentication-failure-url="/loginfailed"/>
<security:logout logout-success-url="/logout"/>
</security:http>
<security:authentication-manager>
<security:authentication-provider>
<security:user-service>
<security:user name="Admin" password="Admin123" authorities="ROLE_ADMIN"/>
</security:user-service>
</security:authentication-provider>
</security:authentication-manager>
</beans>我该怎么做才能使它正确？
回答 2
Stack Overflow用户
发布于 2018-10-04 00:43:10
检查csrf令牌
如果在post url中使用表单标记，则应使用令牌参数发送。
<form>
<input type="hidden" th:name="${_csrf.parameterName}" th:value="${_csrf.token}"/>
</form>或
@Configuration
@EnableWebSecurity
@EnableOAuth2Sso
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
http
.csrf().disable()应该允许在安全配置中使用url
@Configuration
@EnableWebSecurity
@EnableOAuth2Sso
public class SecurityConfiguration extends WebSecurityConfigurerAdapter {
http
.csrf().disable()
.authorizeRequests()
.antMatchers(HttpMethod.POST, "/j_spring_security_check").permitAll()Stack Overflow用户
发布于 2018-10-04 05:12:21
其原因是请求不包含csrf令牌，因为spring安全自动启用它，所以csrf令牌必须与请求一起发送。简单地禁用它并不是一个好主意，这会让整个应用程序完全打开。
将以下隐藏输入添加到窗体中，
<input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}"/>如果要禁用csrf支持，请在security-context.xml中使用此功能。(春季4+)
<http>
<csrf disabled="true"/>
</http>页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接：
https://stackoverflow.com/questions/52636087
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