按特定时间间隔获取脚本列表的Crontab

Question

我们如何使用python获得在crontab中运行的脚本列表--比如4:00PM到8:00PM --我得到的是用户在crontab中运行的所有作业的列表，但在那个特定的时间无法得到。

尝试过这样做：

得到所有脚本的列表。

from crontab import CronTab
import datetime
import croniter

cron = CronTab("user")

for j in cron:
   print j

试图在那个特定的时间之间：

from crontab import CronTab
import datetime
import croniter

cron = CronTab("pfmuser")

for j in cron:
    hour = int(j.split()[1])
    minutes = int(j.split()[0])
    if hour >= 16 and hour <= 20:
        print('fond a job running between 16 and 20')

获得错误:AttributeError：'CronItem‘对象没有属性’拆分‘

错误已完成，但

***but now i have:
1) 10 0 * * 5
2)  0 3 1 * *
3)  0 0 * * *
4)  0 1 * * *
5)  0 10 * * * 

now if have some problem and the cron scripts didnt run then if i am running for 0-10th hour then i need only 

3)  0 0 * * *
4)  0 1 * * *
5)  0 10 * * *  
these scripts only should run 

1) 10 0 * * 5  (only friday)
2)  0 3 1 * * (only 1st month)
these should not run 

how to  keep  this may be can i use datetime and get that particular details later compare with the cron info.How do i go*** 

编辑脚本，并提出以下建议：

from crontab import CronTab
import datetime
from croniter import croniter as ci

cron = CronTab("pfmuser")

for cronitem in cron:

    cronitemstr = str(cronitem)
    hour = cronitemstr.split()[1]
    minutes = cronitemstr.split()[0]
    minutesint = None
    hourint = None
    try:
        hourint = int(hour)
        minutesint = int(minutes)
    except ValueError as e:
        print e.message
    if hourint >= 16 and hourint <= 20:
        cronitemstr = cronitemstr[:cronitemstr.index(cronitemstr.split()[5])]

        min=cronitemstr.split()[0]
        dom=cronitemstr.split()[2]
        mon=cronitemstr.split()[3]
        dow=cronitemstr.split()[4]
       date_time=datetime.datetime.now()
        try:
           if(min=='*' and dom=='*' and mon=='*' and dow=='*' ):
                print cronitemstr
                print cronitem
           else:
                print "none"
        except Exception as e:
            print "e"

在if子句中需要包括更多的条件，就像我们需要包含更多的条件一样

• 16 **3: dis就像今天星期四16小时一样，它需要工作，所以这个脚本也应该显示出来。
• 16 ** 1-5 :表示mon，tues，wed，thur，this，它应该运行，所以这也应该显示。
• 16 * 10 *：意味着每天在第10个月的16小时，它需要execute..so，这也应该显示像这样，我们需要检查许多条件。据我所知，我认为我需要考虑今天的日期，比如datetime.date.today()，从那开始，我需要与think表达式进行比较。实际上，* 16 ***意味着所有的脚本在16小时，每天，month.this将仅仅是一个例子，需要考虑所有需要包括的

Answer 1

cronitem对象不是字符串，因此没有属性拆分。在你尝试分裂之前，你可以把它投到一个str上。例如：

from crontab import CronTab
import datetime
from croniter import croniter as ci

cron = CronTab("pfmuser")



for cronitem in cron:

    cronitemstr = str(cronitem)
    hour = cronitemstr.split()[1]
    minutes = cronitemstr.split()[0]
    minutesint = None
    hourint = None
    try:
        hourint = int(hour)
        minutesint = int(minutes)
    except ValueError as e:
        print e.message

    print hourint
    print minutesint
    if hourint >= 16 and minutesint <= 20:
        print('found a job running between 16 and 20')

        cronitemstr = cronitemstr[:cronitemstr.index(cronitemstr.split()[5])]
        iter = ci(cronitemstr)
        next_run = iter.get_next()
        last_run = iter.get_prev()
        next_run_datetime = datetime.datetime.fromtimestamp(next_run)
        last_run_datetime= datetime.datetime.fromtimestamp(last_run)
        print 'the next run is at {}'.format(next_run_datetime)
        print 'the last run was at {}'.format(last_run_datetime)