从特定的开始日期对天数数组进行排序。

Question

我把这些日子按随机顺序排列：

$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";

如果我们今天是一个“星期二”，我希望有一个新的数组：

$jour_planning[] = "wednesday";
$jour_planning[] = "thursday";
$jour_planning[] = "friday";
$jour_planning[] = "saturday";
$jour_planning[] = "sunday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";

用usort()怎么能做到这一点？

你好，维安尼

Answer 1

您可以使用uksort()、date()和strtotime()重新排列数组。

function sort_week_days( $t1, $t2 ) {
        $weekdays = array( 'sunday', 'monday', 'tuesday', 'wednesday', 'thursday', 'friday', 'saturday' );
        foreach ( $weekdays as $key => $value ) {
            $weekdays[ $key ] = date( 'w', strtotime( $value ) );
        }

        $t1_time = date( 'w', strtotime( strtolower( $t1 ) ) );
        $t2_time = date( 'w', strtotime( strtolower( $t2 ) ) );

        return array_search( $t1_time, $weekdays ) - array_search( $t2_time, $weekdays );
    }

您需要按以下方式传递随机数组：

usort($jour_planning, "sort_week_days");

然后可以在下面的代码中使用数组：

$day = date('w'); // You need to change to date('w', '-1day'); get result from today.

for ($i=0; $i <= $day ; $i++) {
   array_push($jour_planning, array_shift($jour_planning));
}   

Answer 2

我首先对数组进行排序(并避免使用法语和英语命名:)。

然后，将数组排序并存储为2的循环将数组分离为预期数组的前几天(包括这一天)和第二天。

最后，合并两个数组。

当然有更好的方法来做到这一点。

$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";

$sorted_days_planning = array(1 => null, 2 => null, 3 => null, 4 => null, 5 => null, 6 => null, 7 => null);

foreach ($jour_planning as $value)
{
    $day_of_week = date('N', strtotime($value));
    $sorted_days_planning[$day_of_week] = $value;
}

$final_days_planning = array();

$day_to_start = "tuesday";
$day_found = false;
$temp_array = array();
foreach ($sorted_days_planning as $value)
{
    if (!$day_found)
    {
        $temp_array[] = $value;
        if ($day_to_start == $value)
            $day_found = true;
    }
    else
        $final_days_planning[] = $value;
}

$final_days_planning = array_merge($final_days_planning, $temp_array);

var_dump($final_days_planning);

产出：

array(6) {
    [0]=> string(9) "wednesday"
    [1]=> string(8) "thursday"
    [2]=> string(6) "friday"
    [3]=> string(8) "saturday"
    [4]=> string(6) "sunday"
    [5]=> string(6) "monday"
    [6]=> string(7) "tuesday"
}

Answer 3

由于数组是随机排序的，因此没有其他方法可以正确排序，然后手工进行排序(不能按数字或字母顺序对数组进行排序--可以通过datetime()函数计算天数来完成，参见@Cid's答案)，因此：

/*
$jour_planning = [];

$jour_planning[] = "friday";
$jour_planning[] = "wednesday";
$jour_planning[] = "monday";
$jour_planning[] = "tuesday";
$jour_planning[] = "thursday";
$jour_planning[] = "sunday";
$jour_planning[] = "saturday";
*/

$days = [
    0 => 'monday',
    1 => 'tuesday',
    2 => 'wednesday',
    3 => 'thursday',
    4 => 'friday',
    5 => 'saturday',
    6 => 'sunday'
];

$today = array_search(strtolower(date('l')), $days);
$tomorrow = ($today === 6) ? 0 : $today + 1;
$reordered = array_merge(array_slice($days, $tomorrow), array_slice($days, 0, $tomorrow));

print_r($reordered);

首先你必须搜索当前的一天，然后在这一天的索引中添加1，你就有了这一天，那就是明天。现在，当您拥有这个索引时，只需创建两个数组:第一个从明天开始，第二个从索引0开始到今天。然后将这两个数组合并在一起，您就得到了您想要的结果。