筛选一个数组，其中第一个数组中的值包含类型记录中第二个数组中的值。

Question

在类型记录中，我有两个数组：

var StarWarsChars: any = [
      "Jedi Yoda",
      "Jedi Mace Windu",
      "Jedi Qui-Gon Jinn",
      "Jedi Qui-Gon Jinn",
      "Jedi Obi-Wan Kenobi",
      "Sith Count Dooku",
      "Sith Darth Sidious",
      "Droid R2-D2",
      "Droid R2-D2",
      "Droid C-3PO",
      "Droid BB-8"
    ];

var StarWarsFilter: any = ["Jedi", "Sith"];

我希望创建第三个数组，该数组由来自StarWarsChars数组的值组成，其中值包含StarWarsFilter中的值。我知道如何对单个值进行筛选：

var StarWarsFiltered = StarWarsChars.filter(e =>
      e.includes(StarWarsFilter[0])
    );

返回：

0: "Jedi Yoda"
1: "Jedi Mace Windu"
2: "Jedi Qui-Gon Jinn"
3: "Jedi Qui-Gon Jinn"
4: "Jedi Obi-Wan Kenobi"

但我不知道如何对StarWarsFilter中的所有值执行此筛选。我可以尝试一个循环，但我想有一个更好的方法。

Answer 1

首先，我建议对数组使用正确的类型：string[]

您应该能够做到以下几点：

var StarWarsChars: string[] = [
  "Jedi Yoda",
  "Jedi Mace Windu",
  "Jedi Qui-Gon Jinn",
  "Jedi Qui-Gon Jinn",
  "Jedi Obi-Wan Kenobi",
  "Sith Count Dooku",
  "Sith Darth Sidious",
  "Droid R2-D2",
  "Droid R2-D2",
  "Droid C-3PO",
  "Droid BB-8"
];

var StarWarsFilter: string[] = ["Jedi", "Sith"];

var StarWarsFiltered = StarWarsChars.filter(e =>
      StarWarsFilter.some(f => e.includes(f))
);

Answer 2

const StarWarsFiltered = StarWarsChars.filter(x => x.split(' ').some(y => StarWarsFilter.includes(y)));

这将返回StarWarsChars中包含StarWarsFilter中一个单词的所有项。