我正在尝试使用env_tensorflow库从称为pybind11的python环境中执行python解释器。
即使我将cpp文件包括并链接到来自该环境(env_tensorflow)的env_tensorflow库,解释器还是将其二进制路径打印为:
/usr/bin/python3 3
但是,我希望输出如下:
/home/user/miniconda3/envs/env_tensorflow/bin/python3
我做错了什么?如何从特定的环境运行python解释器?
main.cpp
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/Python.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/pybind11.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/embed.h"
namespace py = pybind11;
int main() {
py::scoped_interpreter guard{};
py::module sys = py::module::import("sys");
py::print(sys.attr("executable"));
//prints: /usr/bin/python3
//expected print: /home/user/miniconda3/envs/env_tensorflow/bin/python3
return 0;
}CMakeLists.txt
cmake_minimum_required(VERSION 3.12)
project(my_proj)
set(CMAKE_CXX_STANDARD 11)
add_library(my_python3.6m SHARED IMPORTED)
set_target_properties(my_python3.6m PROPERTIES
IMPORTED_LOCATION "/home/user/miniconda3/envs/env_tensorflow/lib/libpython3.6m.so"
INTERFACE_INCLUDE_DIRECTORIES "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/"
)
add_executable(my_proj main.cpp)
target_link_libraries(my_proj my_python3.6m)发布于 2018-09-24 14:34:20
您需要激活Conda环境:
source activate env_tensorflow一旦您这样做了,您应该能够使用正确的Python解释器运行cmake、make和您的应用程序。您可能不需要CMake中导入的目标,只要环境在构建过程中处于活动状态,就可以正常地链接到python3.6m。
https://stackoverflow.com/questions/52478788
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