我正试图改变现状。下面的表达式考虑到月到日之间的额外空间如下:
(?:(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\s\d{1,2}\s\d{1,2}:\d{1,2}
rats 1.4K Sep 9 08:10 /opt/rats/prod ===> it returns blank
rats 1.4K Sep 12 08:10 /opt/rats/prod ===> returns "Sep 12 08:10"
If I add \s it works in the first string but it breaks on the second string:
(?:(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\s\s\d{1,2}\s\d{1,2}:\d{1,2}谢谢
发布于 2018-09-20 21:33:08
完全匹配额外的空间
(?:(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\s{1,2}\d{1,2}\s\d{1,2}:\d{1,2}与任何额外的空格数相匹配
(?:(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))\s+\d{1,2}\s\d{1,2}:\d{1,2}发布于 2018-09-20 21:31:36
您可以试试这个:\s{1}\d{2}或\s{2}\d{1}
(?:(Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec))(\s{1}\d{2}|\s{2}\d{1})\s\d{1,2}:\d{1,2}https://stackoverflow.com/questions/52433488
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