保持相同的会话FBSDKLoginKit，FBSDKShareKit 4.36

Question

我使用FBSDKLoginKit和FBSDKShareKit登录和共享FBSDKShareOpenGraphContent之后。

我在android中也有类似的行为，而且效果很好。

我可以在Facebook上快速登录，但当我调用FBSDKShareDialog.show(从: self，with: content，委托: nil)从一个详细视图控制器共享我的FBSDKShareOpenGraphContent时，应用程序再次在浏览器中显示登录FACEBOOK页面！我原以为FBSDKShareOpenGraphContent是直接共享的，而不需要再次登录！

如果FBSDKAccessToken.currentAccessTokenIsActive()返回true，为什么会出现这种行为？如何在不同的视图控制器之间保持相同的会话？我读了很多关于它的帖子，这些解决方案并不能解决我的问题

请注意，如果我第二次输入用户和密码并重新登录，FBSDKShareOpenGraphContent将被正确共享！但是是一个糟糕的用户体验，我希望用户只需登录1次！

请帮助这里是我的密码：

//APPDELEGATE

      func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
                // Override point for customization after application launch.

                FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)
                          return true
            }

            private func application(application: UIApplication, didFinishLaunchingWithOptions launchOptions: [NSObject: AnyObject]?) -> Bool {
                // Override point for customization after application launch.
                return FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: launchOptions)
            }

            private func application(application: UIApplication, openURL url: URL, sourceApplication: String?, annotation: Any?) -> Bool {
                return FBSDKApplicationDelegate.sharedInstance().application(
                    application,
                    open: url as URL?,
                    sourceApplication: sourceApplication,
                    annotation: annotation)
            }
    func applicationDidBecomeActive(_ application: UIApplication) {
            // Restart any tasks that were paused (or not yet started) while the application was inactive. If the application was previously in the background, optionally refresh the user interface.
            FBSDKAppEvents.activateApp()
        }

    ----

//登录VIEWCONTROLLER @IBAction

    @IBAction func fbLoginButtonTapped(_ sender: UIButton) {
            let fbLoginManager : FBSDKLoginManager = FBSDKLoginManager()
            fbLoginManager.logIn(withReadPermissions: ["public_profile"], from: self) { (result, error) -> Void in
                if (error == nil) {

                    let fbloginresult : FBSDKLoginManagerLoginResult = result!
                    // if user cancel the login
                    if (result?.isCancelled)! {
                        print("LOGIN FB CANCELLED")
                        return
                    }
                    if(fbloginresult.grantedPermissions.contains("public_profile")) {
                        print("LOGIN FB SUCCESS")
                        /* DO MY STUFF */   
                    }
                } else {
                    print("LOGIN FB ERROR")
                }
            }
        }

   //Page Detail ViewController with share button @IBAction

     @IBAction func facebookButtonTapped(_ sender: UIButton) {
                if (FBSDKAccessToken.currentAccessTokenIsActive() == true) {
//THIS RETURNS TRUE AS USER IS ALWAYS LOGGED

                    let properties = ["og:type": "article",
                                      "og:title": "\(self.post?.title ?? "")",
                        "og:image": "\(self.post?.image ?? "")",
                        "og:description": "\(self.post?.content ?? "")"]

                    let object: FBSDKShareOpenGraphObject = FBSDKShareOpenGraphObject(properties: properties)

                    let action: FBSDKShareOpenGraphAction = FBSDKShareOpenGraphAction(type: "news.reads", object: object, key: "article")
                    let content: FBSDKShareOpenGraphContent = FBSDKShareOpenGraphContent()
                    content.action = action
                    content.previewPropertyName = "article"
                    FBSDKShareDialog.show(from: self, with: content, delegate: nil)
                }
        }

用于Facebook集成的Info.plist

 <!-- FBSDK INTEGRATION -->
    <key>CFBundleURLTypes</key>
    <array>
        <dict>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>fb************</string>
            </array>
        </dict>
    </array>
    <key>FacebookAppID</key>
    <string>**************</string>
    <key>FacebookDisplayName</key>
    <string>*********</string>

    <key>LSApplicationQueriesSchemes</key>
    <array>
        <string>fbapi</string>
        <string>fb-messenger-api</string>
        <string>fbauth2</string>
        <string>fbshareextension</string>
    </array>

登录按钮点击后显示的第一个登录页面：

再次登录页面，在第一次登录成功后，单击“共享”按钮。

Answer 1

我用以下代码解决了这个问题：

 let shareDialog = FBSDKShareDialog()
 shareDialog.delegate = self
shareDialog.shareContent = content

if (UIApplication.shared.canOpenURL( URL(string: "fbauth2:/")!) ) {
    shareDialog.mode = .native
} else {
    shareDialog.mode = .web
}

shareDialog.show()

以前我用过

shareDialog.mode = .auto

但是，如果这不能选择要做的适当的事情，或者由于某种原因而失败，那么似乎重新实例化了一个web浏览器，而没有保持活动会话。

使用模式.native和.web，我可以处理本机应用程序安装与否的情况，同时保持活动会话。