Oracle数据透视选项

Question

我有下面的枢轴和输出。我想展示下面的内容。

1. 删除列周围的括号？
2. 添加X和Null的指示剂代替1和0？

SQL：

SELECT DISTINCT
*
   FROM (
          SELECT D.ID, D.DI, A.ID
          FROM  A
          LEFT JOIN  AD                  ON A.ID = AD.ID
          LEFT JOIN  D                        ON AD.ID = D.ID
          WHERE 1=1
          AND A.ID = 890929
                                           )
          PIVOT
            (
           COUNT(ID) 
            FOR DI IN  ( 'Low med','Soft','Regular','High Med','Other')
              )

查询输出：

ID  'Low med' 'Soft' 'Regular'  'High Med'  'Other'
1      1         1      0           0          1

预期产出：

ID  LOW_MED    SOFT REGULAR        HIGH_MED       OTHER
1      X         X      NULL           NULL          X

Answer 1

您可以通过混叠旋转表达式来删除单引号(不是括号，即())：

FOR DI IN ('Low med' as low_med, 'Soft' as soft, 'Regular' as regular,
  'High Med' as high_med,'Other' as other)

然后，您可以在第二部分中使用这些别名，但是可以将大小写表达式添加到主查询中：

SELECT id,
  case when low_med = 1 then 'X' else null end as low_med,
  case when soft = 1 then 'X' else null end as soft,
  case when regular = 1 then 'X' else null end as regular,
  case when high_med = 1 then 'X' else null end as high_med,
  case when other = 1 then 'X' else null end as other
FROM (
  SELECT D.ID, D.DI, A.ID
  FROM  A
  LEFT JOIN  AD ON A.ID = AD.ID
  LEFT JOIN  D ON AD.ID = D.ID
  WHERE 1=1
  AND A.ID = 890929
)
PIVOT
(
  COUNT(ID) 
  FOR DI IN ('Low med' as low_med, 'Soft' as soft, 'Regular' as regular,
    'High Med' as high_med,'Other' as other)
)