我有张桌子,看起来像这样:
Month/Year id url kw_count IMP CLK POS CTR
Aug-2018 1 /url-1 222 444 122 4 1.2
Sept-2018 2 /url-1 232 534 123 4 1.2
Oct-2018 3 /url-1 224 445 124 4 1.2
Nov-2018 4 /url-1 212 478 125 4 1.2
Aug-2018 5 /url-2 233 434 126 4 1.2
Sept-2018 6 /url-2 311 433 128 4 1.2
Oct-2018 7 /url-2 299 423 123 4 1.2
Nov-2018 8 /url-2 232 411 122 4 1.2
Dec-2018 9 /url-2 231 465 156 5 1.1 我想选择所有唯一的urls和他们的度量两个单独的月。像这样的…2018年8月和9月…
/url-1, kw_count (aug), kw_count (sept), imp (aug), img (sept)...等,然后同样适用于url-2。
我不知道之前的网址-手,这是简单的选择根据选定的日期。
我一辈子都想不出该怎么做。我曾经和group by和其他人一起玩过,但我正在挣扎。
我该怎么做?
发布于 2018-08-23 22:29:08
像这样的事情应该做你想做的事:
SELECT url,
SUM(CASE WHEN `Month\Year` = 'Aug-2018' THEN kw_count END) AS `kw_count (Aug)`,
SUM(CASE WHEN `Month\Year` = 'Sep-2018' THEN kw_count END) AS `kw_count (Sep)`,
SUM(CASE WHEN `Month\Year` = 'Aug-2018' THEN IMP END) AS `IMP (Aug)`,
SUM(CASE WHEN `Month\Year` = 'Sep-2018' THEN IMP END) AS `IMP (Sep)`,
SUM(CASE WHEN `Month\Year` = 'Aug-2018' THEN CLK END) AS `CLK (Aug)`,
SUM(CASE WHEN `Month\Year` = 'Sep-2018' THEN CLK END) AS `CLK (Sep)`,
SUM(CASE WHEN `Month\Year` = 'Aug-2018' THEN POS END) AS `POS (Aug)`,
SUM(CASE WHEN `Month\Year` = 'Sep-2018' THEN POS END) AS `POS (Sep)`,
SUM(CASE WHEN `Month\Year` = 'Aug-2018' THEN CTR END) AS `CTR (Aug)`,
SUM(CASE WHEN `Month\Year` = 'Sep-2018' THEN CTR END) AS `CTR (Sep)`
FROM metrics
GROUP BY url输出(用于样本数据):
url kw_count (Aug) kw_count (Sep) IMP (Aug) IMP (Sep) CLK (Aug) CLK (Sep) POS (Aug) POS (Sep) CTR (Aug) CTR (Sep)
/url-1 222 232 444 534 122 123 4 4 1 1
/url-2 233 311 434 433 126 128 4 4 1 1生成查询时,需要适当地调整日期和列名。我已经创建了一个演示SQLFiddle来播放(如果你发布文本而不是你的数据的图片,那就容易多了!)
发布于 2018-08-23 22:28:55
您的表包含每个月的记录和url。现在选择一个月,选择另一个月,加入两个数据集,您就完成了。这将是:
select *
from (select * from mytable where month_year = 'Aug-2018') m201808
full outer join (select * from mytable where month_year = 'Sept-2018') m201809 using (url);由于MySQL不支持完全外部连接,因此我们必须先获得urls,然后才能在两个月内获得外部连接:
select *
from (select distinct url from mytable where month_year in ('Aug-2018', 'Sept-2018')) urls
left join (select * from mytable where month_year = 'Aug-2018') m201808 using (url)
left join (select * from mytable where month_year = 'Sept-2018') m201809 using (url);当然,您应该将select *替换为列名:
select
url,
m201808.kw_count as kw_count_201808,
m201809.kw_count as kw_count_201809,
...https://stackoverflow.com/questions/51994937
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