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GAMLSS错误:响应变量超出范围
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Stack Overflow用户
提问于 2018-08-21 23:28:35
回答 1查看 1.5K关注 0票数 4

我搞不懂我为什么会收到这个错误。我的两个变量都是数值变量,长度都是相同的,当它们不是NAs时,我用NAs来调整数据;但是,我仍然收到一个错误,即响应变量超出了范围。

代码语言:javascript
复制
    year <- c(1,2,3,4,5,6,7,8,9,10)
    y <- c(19.36, 0, 0, 0.06, 0,0, 1.58, 2.37, 0,0)
    x1 <- c(99.735835998,32.73874517,10.8545887,47.96341768,6.29940882,22.55498627,16.64656661,4.234896268,0.571722269,53.45872813)

    months = c("Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec")

    Drivers = c("P","T")
    ModelName = paste0(Drivers[1],"_",Drivers[2])
    ModelNumb = 2

for (s in 1:length(months))
{

  station_summary = data.frame(matrix(NA,length(stations),3))
  colnames(station_summary)=c("Station", "ModelName", "ModSelection")
  month = months[s]

  for (se in 1:length(stations))
  {

    station = stations[se]
    table = read.csv(paste0("D:/BF_Factors/Regroup Drivers/All_Drivers_BF_P_T/",station,"/Table_",station,"_",month,".csv"),sep=",",header = T)
    table = subset(table, select=c("Year","BF",Drivers))
    table = table[1:50,]

    # Clean the data according to the model used. Some years have been excluded because no data where available

    table[is.na(table[,2]),3] = NA
    table[is.na(table[,2]),4] = NA
    table[is.na(table[,3]),2] = NA
    table[is.na(table[,3]),4] = NA
    table[is.na(table[,4]),2] = NA
    table[is.na(table[,4]),3] = NA

    if (length(which(table[,2]>0))>=5) # If at least 5 values are higher than 0
    {

      x1 = table$P #first Driver
      x2 = table$T

     mod.GA1 <- gamlss(y~x1,sigma.fo=~1,family=GA) 
     mod.GA2 <- gamlss(y~x1+x2,sigma.fo=~1,family=GA)

gamlss中的错误(公式=表$BF~ x1 + x2,族= GA):响应变量超出范围:有50个或更多警告(使用警告()查看前50)

EN

回答 1

Stack Overflow用户

发布于 2019-05-24 11:54:48

问题在于y变量中的0值。如果响应变量中有0,则无法将GAMLSS与Gamma分布相匹配。

注意:您的示例中的代码是不可复制的,所以我无法理解在处理数据之后,您是否仍然在y变量中得到了0。

票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/51957993

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