是否有方法用Ramda覆盖object中的支柱名称？

Question

我有一个对象，{thing1: {}, thing2: {}}，有一种方法可以覆盖像{thing1: {}, thing3not2: {}}这样的道具名称

Answer 1

不确定是否有一种更快/更简单的方法，但是可以将assoc添加新键和dissoc组合以删除旧键：

​

const { curry, assoc, dissoc } = R;

const renameProp = curry(
  (oldName, newName, obj) =>
    dissoc(oldName, assoc(newName, obj[oldName], obj))
);
  
  
const myTransformation = renameProp("thing2", "thing3not2");

const myResult = myTransformation( {thing1: {}, thing2: {} } );

console.log(JSON.stringify(myResult, null, 4));

<script src="https://cdn.jsdelivr.net/npm/ramda@0.25.0/dist/ramda.min.js"></script>

​

Answer 2

Ramda“食谱”包含一个renameKeys函数https://github.com/ramda/ramda/wiki/Cookbook#rename-keys-of-an-object

下面是从那里复制的：

/**
 * Creates a new object with the own properties of the provided object, but the
 * keys renamed according to the keysMap object as `{oldKey: newKey}`.
 * When some key is not found in the keysMap, then it's passed as-is.
 *
 * Keep in mind that in the case of keys conflict is behaviour undefined and
 * the result may vary between various JS engines!
 *
 * @sig {a: b} -> {a: *} -> {b: *}
 */
const renameKeys = R.curry((keysMap, obj) =>
  R.reduce((acc, key) => R.assoc(keysMap[key] || key, obj[key], acc), {}, R.keys(obj))
);

并称之为

renameKeys({thing2: 'thing3not2'}, {thing1: {}, thing2: {}})
=> {"thing1": {}, "thing3not2": {}}