显示多个子页WordPress

Question

我有一个Multisite安装：

1:主站点- domain.com

2:其他网站-domain.com/ other

修复：到目前为止还不错。我的脚本自动显示标题下面的内容，而不是插入我的短代码的位置。

function subsites_list_sites() {
    $subsites = get_sites();    
    if ( ! empty ( $subsites ) ) {  
        echo '<div class="subsites-container">';
        foreach( $subsites as $subsite ) {
            $subsite_id = get_object_vars( $subsite )["blog_id"];
            $subsite_name = get_blog_details( $subsite_id )->blogname;
            $subsite_link = get_blog_details( $subsite_id )->siteurl;
            echo '<div class="subtite-item site-' . $subsite_id . '">
            <a class="thumb" href="' . $subsite_link . '">Here i want the featured image/thumbnail to display</a>
            <a class="title-link" href="' . $subsite_link . '"><h3 class="title">' . $subsite_name . '</h3></a>
            <a class="excerpt" href="' . $subsite_link . '"><p>Here i want excerpt<p></a>
            <a class="btn-link" href="' . $subsite_link . '">GO TO WEBSITE</a>
            </div>';
        }
        echo '</div>';
    }
}
add_shortcode( 'subsites_list_sites_sc', 'subsites_list_sites' );

Answer 1

短代码应该返回html，而不是在短代码函数中打印它。

就像这样：

function subsites_list_sites() {
    $subsites = get_sites();
    $returnHtml = '';    
    if ( ! empty ( $subsites ) ) {  
        $returnHtml .= '<div class="subsites-container">';
        foreach( $subsites as $subsite ) {
            $subsite_id = get_object_vars( $subsite )["blog_id"];
            $subsite_name = get_blog_details( $subsite_id )->blogname;
            $subsite_link = get_blog_details( $subsite_id )->siteurl;
            $returnHtml .= '<div class="subtite-item site-' . $subsite_id . '">
            <a class="thumb" href="' . $subsite_link . '">Here i want the featured image/thumbnail to display</a>
            <a class="title-link" href="' . $subsite_link . '"><h3 class="title">' . $subsite_name . '</h3></a>
            <a class="excerpt" href="' . $subsite_link . '"><p>Here i want excerpt<p></a>
            <a class="btn-link" href="' . $subsite_link . '">GO TO WEBSITE</a>
            </div>';
        }
        $returnHtml .= '</div>';
    }
    return $returnHtml;
}

输出 将将短代码处理程序函数的返回值插入post内容输出，而不是将其插入到短代码宏中。记住使用返回而不是回显--任何回显的内容都会输出到浏览器，但是它不会出现在页面的正确位置。API#Output