在MQL5中接受Python生成的套接字的输出

Question

我已经创建了一个套接字文件，如下所示，并希望套接字的输出必须由MQL5读取。请参阅以下Python代码：

daemon.py

import socket
#import arcpy

def actual_work():
    #val = arcpy.GetCellValue_management("D:\dem-merged\lidar_wsg84", "-95.090174910630012 29.973962146120652", "")
    #return str(val)
    return 'dummy_reply'


def main():
    sock = socket.socket( socket.AF_INET, socket.SOCK_DGRAM )
    try:
        sock.bind( ('127.0.0.1', 6666) )

        while True:
            data, addr = sock.recvfrom( 4096 )
            reply = actual_work()
            sock.sendto(reply, addr)
    except KeyboardInterrupt:
        pass
    finally:
        sock.close()


if __name__ == '__main__':
    main()

client.py

import socket
import sys


def main():
    sock = socket.socket( socket.AF_INET, socket.SOCK_DGRAM )
    sock.settimeout(1)
    try:
        sock.sendto('', ('127.0.0.1', 6666))
        reply, _ = sock.recvfrom(4096)
        print reply
    except socket.timeout:
        sys.exit(1)
    finally:
        sock.close()


if __name__ == '__main__':
    main()

请帮助我通过MQL5接受套接字的输出。

编辑的

我只想让reply在由daemon.py生成的变量中在MQL5上被接受。我怎么能这么做？假设我希望MQL5输出来自Python的响应，就像上面的例子一样，如果可能的话，MQL5应该在字符串变量中以dummy_reply的形式给出输出。

ZeroMQ有什么可能吗？

我想让client.py使用MQL5来完成，而不是使用MQL5。请帮帮我。

Answer 1

请找一个正在运行的例子。重要元素是在发送应答之前创建有效负载的字节对象，而不是字符串。套接字对象只生成和摄取字节。

    import socket
    import threading
    import sys


    def actual_work(data):
       print(data)
       return b'ACK'

    def daemon():
       sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
       sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
       sock.bind(('127.0.0.1', 6666))
       print("Listening on udp %s:%i" % ('127.0.0.1', 6666))
       try:

          while True:
              data, addr = sock.recvfrom(4096)
              ack = actual_work(data)
              sock.sendto(ack, addr)
       except Exception as e:
          print(e)  
       finally:
          sock.close()


    def client():
       sock = socket.socket( socket.AF_INET, socket.SOCK_DGRAM )
       sock.settimeout(1)
       try:
           sock.sendto(b'payload', ('127.0.0.1', 6666))
           reply, _ = sock.recvfrom(4096)
           print(reply)
       except socket.timeout as e:
           print(e)
           sys.exit(1)
       finally:
           sock.close()

    if __name__ == '__main__':
        thread = threading.Thread(target=daemon)
        thread.start()
        client()
        client()
        client()
        client()
        #Issue kill thread here
        thread.join()